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KatRina [158]
2 years ago
15

HURRY 20 POINTS Why is it important to include exercise in your daily routine?

Physics
1 answer:
Sedbober [7]2 years ago
3 0

Explanation:

it can improve muscle strength and boost your endurance.

it also delivers oxygen and nutrients to your tissues

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Two disks of identical mass but different radii (r and 2r) are spinning on frictionless bearings at the same angular speed ?0, b
cestrela7 [59]

Answer:

Explanation:

Moment of inertia of a disc = 1/2 M R²

Since mass is same for both and radius are r and 2r, their moment of inertia can be in the ratio of 1: 4 . Let them be I and 4I . Angular speed are ω₀ and   - ω₀ .

We shall apply law of conservation of angular momentum .

initial total angular momentum

I x ω₀ - 4I x ω₀ = - 3Iω₀

Let final common angular momentum be ω

total final angular momentum = ( I + 4I ) ω

Applying law of conservation of angular momentum

( I + 4I ) ω =  - 3Iω₀

ω = - 3 / 5 ω₀ .

b )

Initial total rotational K E

= 1/2 I ω₀² + 1/2 4I ω₀²

= 1/2 x5I ω₀²

Final total rotational K E

= 1/2 ( I + 4I ) ( - 3 / 5 ω₀ )²

= 1/2 x 9 / 5 I ω₀²

= 9 / 10I ω₀²

change in rotational kinetic energy = 9 / 10I ω₀² - 1/2 x5I ω₀²

(9/10 - 5/2) xI ω₀²

=( .9 - 2.5 )I ω₀²

= - 1.6 I ω₀² Ans

8 0
3 years ago
ASTM A229 oil-tempered carbon steel is used for a helical coil spring. The spring is wound with D = 50 mm d = 10.0 mm, and a pit
horrorfan [7]

Answer

given,

D = 50 mm = 0.05 m

d = 10 mm = 0.01 m

Force to compress the spring

F = \dfrac{d^4G\delta}{8D^3N}

\dfrac{\delta}{N} = p - d = 14 - 10 = 4 mm

F = \dfrac{d^4G}{8D^3}\times 0.004

F = \dfrac{0.1^4\times 79\times 10^9}{8\times 0.05^3}\times 0.004

     F = 3160 N

stress correction factor from stress correction curve is equal to 1.1

now, calculation of corrected stress

\tau = \dfrac{8FDk_s}{\pi d^3}

\tau = \dfrac{8\times 3160 \times 0.05 \times 1.1}{\pi \times 0.01^3}

              = 442.6 Mpa

The tensile strength of the steel material of  ASTM A229 is equal to 1300 Mpa

now,

\tau_s \leq 0.45 S_u

\tau_s \leq 0.45 \times 1300

\tau_s \leq 585\ Mpa

since corrected stress is less than the \tau_s

hence, spring will return to its original shape.

6 0
3 years ago
Read 2 more answers
What is the minimum speed must a salmon jumping at an angle of 35.2 leave the water in m/s?
yuradex [85]

Height of the waterfall is 0.449 m

its horizontal distance will be 2.1 m

now let say his speed is v with which he jumped out so here the two components of his velocity will be

v_x = vcos35.2 = 0.817 v

v_y = vsin35.2 = 0.576 v

here the acceleration due to gravity is 9.81 m/s^2 downwards

now we can find the time to reach the other end by y direction displacement equation

\Delta y = v_y * t + \frac{1}{2} at^2

-0.449 = 0.576 * v *t - \frac{1}{2}*9.81 * t^2

also from x direction we can say

\Delta x = v_x * t

2.1 = 0.817 v* t

now we have

v* t = 2.57

we will plug in this value into first equation

- 0.449 = 0.576 * 2.57 - 4.905 * t^2

1.93 = 4.905 * t^2

t = 0.63 s

now as we know that

v* t = 2.57

t = 0.63 s

v = \frac{2.57}{0.63}

v = 4.1 m/s

so his minimum speed of jump is 4.1 m/s

8 0
3 years ago
Light enters an equilateral prism with an incident angle of 35° to the normal of the surface. Calculate the angle at which the
julia-pushkina [17]

Answer:

65.9°

Explanation:

When light goes through air to glass

angle of incidence, i = 35°

refractive index, n = 1.5

Let r be the angle of refraction

Use Snell's law

n=\frac{Sini}{Sinr}

1.5=\frac{Sin35}{Sinr}

Sin r = 0.382

r = 22.5°

Now the ray is incident on the glass surface.

A = r + r'

Where, r' be the angle of incidence at other surface

r' = 60° - 22.5° = 37.5°

Now use Snell's law at other surface

\frac{1}{n}=\frac{Sinr'}{Sini'}

Where, i' be the angle at which the light exit from other surface.

\frac{1}{1.5}=\frac{Sin37.5'}{Sini'}

Sin i' = 0.913

i' = 65.9°

4 0
3 years ago
The vacuum inside the thermos bottle shown in Figure 16-1 stops which type of thermal energy transfer to keep the liquid hot
BARSIC [14]
The answer is D- both a and b
7 0
3 years ago
Read 2 more answers
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