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stiv31 [10]
3 years ago
7

Lasers can be constructed that produce an extremely high intensity electromagnetic wave for a brief time—called pulsed lasers. T

hey are used to ignite nuclear fusion, for example. Such a laser may produce an electromagnetic wave with a maximum electric field strength of 1.00×1011V/m for a time of 1.00 ns. (a) What is the maximum magnetic field strength in the wave? (b) What is the intensity of the beam? (c) What energy does it deliver on a 1.00-mm2 area?
Physics
1 answer:
MAVERICK [17]3 years ago
8 0

Explanation:

It is given that,

Maximum electric field, E=10^{11}\ V/m

Time taken, t=1\ ns=10^{-9}\ s

(a) Maximum magnetic field, B=\dfrac{E}{c}

B=\dfrac{10^{11}\ V/m}{3\times 10^8\ m/s}

B = 333.33 T

(b) Intensity of beam, I=\dfrac{E^2}{2\mu_o c}

I=\dfrac{(10^{11})^2}{2\times 4\pi \times 10^{-7}\times 3\times 10^8}

I=1.32\times 10^{19}\ W/m^2

(c) Energy delivered by the pulse, E=I\times A\times t

E=1.32\times 10^{19}\times 10^{-6}\times 10^{-9}

E = 13200 J

Hence, this is the required solution.

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Given that,

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\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm

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IE is the energy required to remove an electron from an atom. As atomic radius increases, the valence electrons get farther from
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