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s344n2d4d5 [400]
3 years ago
11

Two stars are 3.7 1011

Physics
1 answer:
dem82 [27]3 years ago
8 0

Answer:

  L = 5.68 10¹⁷ m

Explanation:

The resolution of the telescope is given by diffraction

            a sin θ = m λ

Where a is the separation of the linear slits, λ  the wavelength, m an integer that determines the order of diffraction

In this case, suppose that the premieres meet Rayleigh's criteria, which establishes that the central maximum of the diffraction of an object coincides with the first minimum of diffraction of the second object. In this case m = 1

            sin θ = λ  / a

In the case of circular openings, polar coordinates must be used, so the equation is

            sin θ = 1.22 λ  / D

Where D is the diameter of the lens or tightness. Since the distances are very large and the small angles we can approximate the sine to the radian angle value

             θ = 1.22 λ  / D

Let's use trigonometry to find the angle. We have the separation of the premieres y = 3.7 10¹¹ m and

          tan θ = y / L

           θ = y / L

Let's replace

           y / L = 1.22 λ  / D

            L = y D / 1.22 λ  

calculate

            L = 3.7 10¹¹  1.03 / (1.22 550 10⁻⁹)

            L = 5.68 10¹⁷ m

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A load of 36 N attached to a spring hanging
Annette [7]

Answer: 115.38N

Explanation:

Firstly, let's determine the constant.

Hooke's law was discovered by Robert Hooke in 1660.

Using hooke's law which states that provided the elastic limit of an elastic material is not exceeded, the force is equal to the extension applied provided all factors are kept constant.

Hooke's Law is a principle of physics that states that the force which is needed to extend or compress a spring by some distance is proportional to that distance

Therefore,

Force=kx

K= F/x

Where Force= 75m

x= 0.065m

K= 75/0.065m

K= 1153. 846N

We can use the constant to find the force when the distance that is stretched(x) is known.

Here

Force=kx

F= 1153.846 × 0.10

F= 115.38N

The force required to stretch it by this amount is 115.38N.

3 0
3 years ago
What’s the resistance in the circuit
inna [77]

Answer:

I = 0.75 A

Explanation:

The question is not to calculate the resistance, but to calculate the current. (The resistance is already given by the value of 2 Ohm).

U = I * R

I = U / R

with U = 1.5 V and R = 2 Ohm

I = 1.5 / 2

I = 0.75 A

3 0
3 years ago
A circular copper loop is placed perpendicular to a uniform magnetic field of 0.50 T. Due to external forces, the area of the lo
pogonyaev

Answer:

6.3\cdot 10^{-4} V

Explanation:

According to Faraday-Newmann-Lenz, the induced emf in the loop is given by:

\epsilon=-\frac{\Delta \Phi}{\Delta t} (1)

where \frac{\Delta \Phi}{\Delta t} is the rate of variation of the magnetic flux through the loop.

We know that the magnetic flux through the loop is given by

\Phi = BA

where B is the magnetic field and A is the area of the loop. Since the magnetic field is constant, we can write the variation of flux as

\Delta \Phi = B \Delta A

So eq.(1) becomes

\epsilon=-B\frac{\Delta A}{\Delta t}

and the problem gives us:

B=0.50 T is the magnetic field

\frac{\Delta \Phi}{\Delta t}=-1.26\cdot 10^{-3} m^2/s is the rate at which the area changes

Substituting into the equation, we find

\epsilon=-(0.50 T)(-1.26\cdot 10^{-3} m^2/s)=6.3\cdot 10^{-4} V=0.63 mV

8 0
3 years ago
The equation y = 2x + 3 represents the cost y (in dollars) of mailing a package that weighs x pounds.
White raven [17]

Answer:

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Explanation:

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6 0
3 years ago
A 100 kg bag of sand has a weight on 100 N. When dropped its acceleration is what?
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To calculate acceleration, divide your weight by the mass, thus the accleration is:

100N/100kg = 1(m/s^2)
7 0
3 years ago
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