Answer:
This process of glycolysis has evolved very early in cells of ancestors and now it has become common to all the life forms on earth
Explanation:
Glycolysis can be simply defined as a biological process in which the glucose particle or the food particles are disintegrated with the help of enzymes. This process releases some amount of energy, along with some acid (pyruvic acid).
Glycolysis is an essential process that takes place inside the cells. It is because the glucose forms the principal source of energy for the development of tissues inside the body. It is helpful in the process of metabolism.
This process takes place in all kinds of living organisms, and has also taken place in the cells of early ancestors.
Answer:
Sunlight allows plants to perform photosynthesis, a process which is required for plant growth and health. ... Plants that are denied sufficient light will eventually lose their color and die. Plants deprived of light will grow upward, stretching their stems more rapidly that usual, searching for light.
Impulse = Ft=mΔv => Δv = Ft/m = 4.28/0.18 = 23.78 m/s
But,
Δv = v1-v2, where v1 = initial velocity = 16 m/s, v2 = final velocity
Therefore,
v1 - v2 = 23.78 => v2 = v1 - 23.78 => v2 = 16 - 23.78 = -7.78 m/s
The velocity of ball after the force is 7.78 m/s in the direction of the force.
(since you asked for basic understanding only, I am not including actual calculations. Please let me know in the comments section if you wish to verify your solution(s))
For (b): Use the formula for distance (s) made during an accelerated motion:
![s = \frac{1}{2}at^2+ v_0t+s_0= \frac{1}{2}at^2= \frac{1}{2}gt^2](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%5E2%2B%20v_0t%2Bs_0%3D%20%5Cfrac%7B1%7D%7B2%7Dat%5E2%3D%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
with v_0 and s_0 being the initial velocity and distance, both 0 in this case, and with "a" denoting the acceleration, in this case solely due to gravitational acceleration so: "g."
You are given the distance made, namely 10 m, and the duration t (0.88s) and so using the formula above you can solve for g.
For (c), to determine the final velocity at time 0.88s use the formula for the instantaneous velocity of an accelerated motion
(velocity at time t) = (acceleration) x (time)
again, with acceleration due to gravity, i.e., a = g and with g as determined under (b).
If my calculation is correct, this mystery planet could be the Jupiter.
Answer:
![h=48.5m](https://tex.z-dn.net/?f=h%3D48.5m)
Explanation:
The loss of gravitational potential energy must be equal to the gain of kinetic energy since there are no other interactions at play (no friction, etc).
We know that the change of potential energy will be written as
, where <em>h</em> is the difference between the different heights.
We know that the change of kinetic energy will be written as
, where <em>v</em> is the final velocity and we have assumed it departs from rest.
We then have:
![mgh=\frac{mv^2}{2}](https://tex.z-dn.net/?f=mgh%3D%5Cfrac%7Bmv%5E2%7D%7B2%7D)
![gh=\frac{v^2}{2}](https://tex.z-dn.net/?f=gh%3D%5Cfrac%7Bv%5E2%7D%7B2%7D)
![h=\frac{v^2}{2g}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7Bv%5E2%7D%7B2g%7D)
We transform km/h to m/s by multiplying by the conversion factors (which are equal to 1, so don't alter the result):
![(\frac{1000m}{1km})(\frac{1h}{3600s})](https://tex.z-dn.net/?f=%28%5Cfrac%7B1000m%7D%7B1km%7D%29%28%5Cfrac%7B1h%7D%7B3600s%7D%29)
So for our values we have:
![h=\frac{((111km/h)(\frac{1000m}{1km})(\frac{1h}{3600s}))^2}{2(9.81m/s^2)}=48.45537m=48.5m](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B%28%28111km%2Fh%29%28%5Cfrac%7B1000m%7D%7B1km%7D%29%28%5Cfrac%7B1h%7D%7B3600s%7D%29%29%5E2%7D%7B2%289.81m%2Fs%5E2%29%7D%3D48.45537m%3D48.5m)
to three significant figures.