<u>Answer:</u>
A plant needing full sun can be placed from a fence 4.63 ft high at a distance of 10.75 meter if the lowest angle of elevation of the sun in winter is 23° 18'.
<u>Explanation:</u>
The given figure shows the arrangement of sun, 4.63 ft high and plant needing full sun.
By using trigonometric result, tan θ = Opposite side/Adjacent side.
Substituting
tan(23° 18') = 4.63 ft/x
x = 4.63 ft/ tan(23° 18') = 10.75 m
So that a plant needing full sun can be placed from a fence 4.63 ft high at a distance of 10.75 meter.
Answer:
unchanged
Explanation:
the box itself has same mass and volume with or without the shoes
The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be
C is 367.42 Hz.
A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.
The fundamental frequency in the tube is given by

where, 
Since, T=37+273 K = 310 K
v = 331 m/s

Using this, we get:

Hence, the fundamental frequency is 367.42 Hz.
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<u>13788 J is required to finish the work.</u>
Explanation:
Given that,
Mass of lawnmower is 20 kg
Force = 30 N

Displacement ( distance moved )= 20m
The force of 30N is applied along the direction of motion and was applied for the whole 20 m.
The formula of work done for one pass is

Substituting the given data into the formula,



W = 459.6 J
Work done for one pass = 459.6J
Now, work done for 30 passes is calculated by multiplying the work done for one pass into 30.

Work is done by the person pushing the mower to finish the work is <u>13788 J</u>.