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notka56 [123]
3 years ago
11

A wire of resistance R is cut into ten equal parts which are then connected in parallel. The equivalent resistance of the combin

ation is
Physics
1 answer:
Greeley [361]3 years ago
6 0

Answer:

<em>The equivalent resistance of the combination is R/100</em>

Explanation:

<u>Electric Resistance</u>

The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.

Parallel connection of resistances: If R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:

\displaystyle \frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...+\frac{1}{R_n}

If we have 10 wires of resistance R/10 each and connect them in parallel, the equivalent resistance is:

\displaystyle \frac{1}{R_e}=\frac{1}{R/10}+\frac{1}{R/10}+\frac{1}{R/10}...+\frac{1}{R/10}

This sum is repeated 10 times. Operating each term:

\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}

All the terms have the same denominator, thus:

\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}

Taking the reciprocals:

R_e=R/100

The equivalent resistance of the combination is R/100

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1.Predict the frequency of a tuning fork that emits a sound with a wavelength of 0.385 m.
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Answer:

1.) Frequency F = 890.9 Hz

2.) Wavelength (λ) = 0.893 m

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1.) Given that the wavelength = 0.385m

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A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 20 m/s by a 5620 N braking force actin
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Answer:

the distance traveled by the car is 42.98 m.

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time of motion of the car, t = 2.5 s

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a = -5620 / 2500

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The distance traveled by the car is calculated as follows;

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