1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
notka56 [123]
3 years ago
11

A wire of resistance R is cut into ten equal parts which are then connected in parallel. The equivalent resistance of the combin

ation is
Physics
1 answer:
Greeley [361]3 years ago
6 0

Answer:

<em>The equivalent resistance of the combination is R/100</em>

Explanation:

<u>Electric Resistance</u>

The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.

Parallel connection of resistances: If R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:

\displaystyle \frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...+\frac{1}{R_n}

If we have 10 wires of resistance R/10 each and connect them in parallel, the equivalent resistance is:

\displaystyle \frac{1}{R_e}=\frac{1}{R/10}+\frac{1}{R/10}+\frac{1}{R/10}...+\frac{1}{R/10}

This sum is repeated 10 times. Operating each term:

\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}

All the terms have the same denominator, thus:

\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}

Taking the reciprocals:

R_e=R/100

The equivalent resistance of the combination is R/100

You might be interested in
What is the function of the wire in
Naily [24]

Answer:

I think the right answer is option B.

3 0
3 years ago
The amount of energy that remains after the amount of energy used for respiration is subtracted from the total is called
lawyer [7]

Answer:Gibb's free energy

Explanation:

The Free energy change describes the amount of energy that is available in any system to do work. It is often designated with the symbol G

4 0
3 years ago
In treatment the so called "nervous " disorder, freuad discovered the most effetive method to be
maks197457 [2]

Answer:

Freud believed that people could be cured by making conscious their unconscious thoughts and motivations, thus gaining insight. The aim of psychoanalysis therapy is to release repressed emotions and experiences, i.e., make the unconscious conscious.

Hope this helps. If it does, please mark me brainliest.

Explanation:

6 0
3 years ago
How does the work required to accelerate a particle from 10 m/s to 20 m/s compare to that required to accelerate it from 20 m/s
poizon [28]

To solve this problem we will apply the energy conservation theorem for which the work applied on a body must be equivalent to the kinetic energy of this (or vice versa) therefore

W = \Delta KE

\Delta W = \frac{1}{2} (m)(v_f)^2 -\frac{1}{2} (m)(v_i)^2

Here,

m = mass

v_{f,i} = Velocity (Final and initial)

First case) When the particle goes from 10m/s to 20m/s

\Delta W = \frac{1}{2} (m)(v_f)^2 -\frac{1}{2} (m)(v_i)^2

\Delta W = \frac{1}{2} (m)(20)^2 -\frac{1}{2} (m)(10)^2

W_1 = 150(m) J

Second case) When the particle goes from 20m/s to 30m/s

\Delta W = \frac{1}{2} (m)(v_f)^2 -\frac{1}{2} (m)(v_i)^2

\Delta W = \frac{1}{2} (m)(30)^2 -\frac{1}{2} (m)(20)^2

W_1 = 250(m) J

As the mass of the particle is the same, we conclude that more energy is required in the second case than in the first, therefore the correct answer is A.

5 0
3 years ago
Consider three resistors with unequal resistances connected in series to a battery. Which of the following statements are true?
Ivenika [448]
<h2>Answer: The second Statement </h2>

<h2>The algebraic sum of the currents flowing through each of the three resistors is equal to the current through the battery.  </h2><h2 />

In a series circuit, the value of the equivalent resistance R_E is equal to the sum of the values of each of them:  

R_ {E}=R_{1}+R_ {2}+R_ {3}  

Where:  

<h2>The equivalent resistance of the combination of resistors is greater than the resistance of any one of three resistors. </h2>

In this case the current I flowing through the resistors is the same in each one. This is because the current flowing through the circuit only has one way to go, so the current intensity is the same throughout the circuit.

Therefore:  

<h2>The current flowing through each of the resistors is the same and is equal to the current through the battery.  </h2><h2>The algebraic sum of the voltages across the three resistors is equal to the voltage across the battery.  </h2>

The battery provides a voltage V_T that is the sum of the different voltages at the ends of the resistors:  

V_{T}=V_{1}+V_{2}+V_{3}  

Where the Voltage, according to Ohm's law is:  

V=R.I  

Hence, the second statement of this question is <u>True </u>

7 0
3 years ago
Other questions:
  • A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. What force must be applied to the s
    13·1 answer
  • Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin
    15·1 answer
  • Pls someone help with number 3
    11·1 answer
  • When white light is passed through a prism, it will
    6·2 answers
  • An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 1.95 mT. If the speed of the
    12·1 answer
  • Kinetic Energy HELP! Brainly included
    14·1 answer
  • A force of 30.0 N is applied to a 3.00 kg object for 3.00 seconds. Calculate the velocity experienced by the object.
    8·1 answer
  • Megan and her brother are watching a television program. Megan notices that the television produces a lot of light. What else do
    15·1 answer
  • ___________ is used mainly in submarines that remain underwater
    5·2 answers
  • The rate of change of momentum of a body free falling under gravity is equal to its? A. Velocity B. kinetic energy C. power D. w
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!