Answer:
Explanation:
The star is revolving the black hole like earth revolves around the sun .so time period of rotation T is given by the following relation
T² = 
, R is distance between black hole and star , M is mass of black hole
Given T = 4.8 hours
4.8² =
Using the same equation for earth sun system
24² = 
, Ms is mass of the sun and 50R is distance between the sun and the earth .
Dividing the equation
= 
= 2x 10⁻⁴
Answer:
As the temperature rises the solubility of all gases in water also will decrease.
Explanation:
The solubility of gases in water increase with the decrease of the temperature, and vice-versa.
The scape of the gas molecules from solution occurs by the breaks of the intermolecular bonds as a consequence of the increase of the kinetic energy which causes an increase in the motion of the gas molecules in solution.
That is why as the temperature rises the solubility of all gases in water also will decrease.
I hope it helps you!
Answer:
The magnitude of the average induced emf is 90V
Explanation:
Given;
area of the square coil, A = 0.4 m²
number of turns, N = 15 turns
magnitude of the magnetic field, B = 0.75 T
time of change of magnetic field, t = 0.05 s
The magnitude of the average induced emf is given by;
E = -NAB/t
E = -(15 x 0.4 x 0.75) / 0.05
E = -90 V
|E| = 90 V
Therefore, the magnitude of the average induced emf is 90V
Answer:
1. T₁ = 500 N
2. T₂ = 866 N
Explanation:
Please see attached photo for the diagram.
Thus, we can obtain obtained the value of T₁ and T₂ as follow:
1. Determination of T₁
Angle θ = 30
Hypothenus = 100 kg
Opposite = T₁ =?
Sine θ = Opposite /Hypothenus
Sine 30 = T₁ / 100
Cross multiply
T₁ = 100 × Sine 30
T₁ = 100 × 0.5
T₁ = 50 Kg
Multiply by 10 to express in Newton
T₁ = 50 × 10
T₁ = 500 N
2. Determination of T₂
Angle θ = 60
Hypothenus = 100 kg
Opposite = T₂ = ?
Sine θ = Opposite /Hypothenus
Sine 60 = T₂ / 100
Cross multiply
T₂ = 100 × Sine 60
T₂ = 100 × 0.8660
T₂ = 86.6 Kg
Multiply by 10 to express in Newton
T₂ = 86.6 × 10
T₂ = 866 N
The final kinetic energy of the skateboarder after she freewheels and did work against friction on the flat section of the path is 4,600 J.
<h3>
Conservation of energy</h3>
The final kinetic energy of the stakeboarder is determined by applying the principle of conservation of energy as shown below;
ΔK.E = -W
K.Ef - K.Ei = -W
where;
- K.Ef is the final kinetic energy
- K.Ei is the initial kinetic energy
- W is work done
K.Ef = K.Ei - W
K.Ef = 5,000 J - 400 J
K.Ef = 4,600 J
Thus, the final kinetic energy of the skateboarder is 4,600 J.
Learn more about kinetic energy here: brainly.com/question/25959744
