Range is the y values or ouputs
domain is inputs or x vvalues
we can use any x value
but at a certain y value, w can't go below that
find thatminimum
find the vertex
for
ax^2+bx+c
the x value of the vertex is
-b/2a
plug that in to the equaiton to get the y value
-b/2a=-(-6)/(2*2)=6/4=3/2
plug that in
2(3/2)^2-6(3/2)-9
2(9/4)-9-9
9/2-18
4.5-18
-13.5
domain=all real numbers
range=from -13.5 to positive infinity
Answer:
46.6
Step-by-step explanation:
A binomial probability density function should be used to represent the probability
<h3>How to determine the type of
probability density?</h3>
The given parameters are:
- Proportion that plays sport, p = 32%
- Number of students selected, p = 50
- The probability, P = (x ≤ 15)
The proportion that plays sport indicates that
68% of the students do not play sport
So, we have two events, which are
- Play sport
- Do not play sport
When there are two possible events, then the binomial probability density function should be used
Read more about binomial probability density at:
brainly.com/question/15246027
#SPJ1
Answer:
1. ΔXYZ is a right Δ with altitude YU.
Given
2. ΔXYZ ~ ΔYUZ
Right Triangle Altitude Similarity Theorem
3. VW || XY
Given
4. ∠VWZ ≅ ∠XYZ
Corresponding angles
5. ∠Z ≅ ∠Z
Reflexive property of congruence
6. ΔXYZ ~ ΔVWZ
AA Similarity postulate
7. ΔYUZ ~ ΔVWZ
Transitive property of similar triangles
Step-by-step explanation:
The first statement is given in the problem. Since we know the altitude of a right triangle, we can use the Right Triangle Altitude Similarity Theorem to say that the triangles formed by the altitude are similar to each other and the original triangle.
Next, we are given in the problem statement that the lines VW and XY are parallel. Therefore, ∠VWZ and ∠XYZ are corresponding angles, which makes them congruent. And since ∠Z is equal to itself (by reflexive property), we can use AA similarity to say ΔXYZ and ΔVWZ are similar.
Finally, combining statements 2 and 6, we can use transitive property to say that ΔYUZ and ΔVWZ are similar.
Answer: 50% of the sandwiches were turkey, 30% were veggie and 20% were tuna.
Step-by-step explanation: The total number of sandwiches sold was 50 in all.
The sales according to type of sandwich were as follows;
25 Turkey
15 Veggie
10 Tuna
50 Total
Since there were 50 sandwiches sold and of these 25 were turkey sandwiches and another 15 were veggie sandwiches, then the remaining which is tuna sandwich is derived as 50 - [25 + 15] which equals 10.
To calculate the percentage per type of sandwich sold;
(a) Turkey is derived as
Percentage turkey = (25/50) x 100
Percentage turkey = 1/2 x 100
Percentage turkey = 50%
(b) Veggie is derived as
Percentage Veggie = (15/50) x 100
Percentage Veggie = (3/10) x 100
Percentage Veggie = 30%
(c) Percentage tuna = (10/50) x 100
Percentage tuna = 1/5 x 100
Percentage tuna = 20%
