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nikdorinn [45]
4 years ago
13

C. Chemical energy. What is the difference in chemical energy between organic and inorganic

Chemistry
1 answer:
Olenka [21]4 years ago
8 0
There are chief differences between organic and inorganic compounds. ... The main difference is in the presence of a carbon atom; organic compounds will contain a carbon atom (and often a hydrogen atom, to form hydrocarbons), while almost all inorganic compounds do not contain either of those two atoms.
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QUESTION: A SCIENTIST NEEDS TO SEPARATE A MIXTURE OF SALT AND WATER. WHICH IF THE FOLLOWING
FromTheMoon [43]

Answer:

nosezjdkdodbdjdlhsjskdn

Explanation:

xdxdxdbzlxjdhfjfyufjfux

4 0
3 years ago
You need to make an aqueous solution of 0.139 M potassium phosphate for an experiment in lab, using a 250 mL volumetric flask. H
Crazy boy [7]

Answer:

7,38 g of K₃PO₄

Explanation:

Molarity is an unit of chemical concentration. 0,139 M means 0,139 moles of solute per liter of solution.

In this case, the solute is potassium phosphate (K₃PO₄; molar mass: 212,27 g/mol) and the volume of the solution must be 250mL≡0,25L.

Thus, the moles of potassium phosphate you need are:

0,139 mol/L×0,25L = 0,03475 moles of K₃PO₄

In grams:

0,03475 moles of K₃PO₄ × \frac{212,27g}{1mol} = 7,38 g of K₃PO₄

I hope it helps!

7 0
4 years ago
Using the atomic masses and relative abundance of the isotopes of nitrogen given below, determine the average atomic mass of nit
masha68 [24]

<span>To calculate the average mass of the element, we take the summation of the product of the isotope mass and the percent abundance. In this case, it is 0.9963 * 14.003 amu + 0.0037* 15.00 amu. This is equal to an average mass of 14.00668889 amu.</span>

8 0
3 years ago
How do I unscramble this?<br><br> nanhglid &amp; tsogera <br><br> handling &amp; _ _ _ _ _ _ _
ahrayia [7]
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7 0
4 years ago
If a compound has a composition of 82% nitrogen and 18% hydrogen, what is the empirical formula for this compound
Damm [24]

Answer: The empirical formula for the given compound is NH_3

Explanation : Given,

Percentage of H = 18 %

Percentage of N = 82 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 18 g

Mass of N = 82 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{18g}{1g/mole}=18moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{82g}{14g/mole}=5.8moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.8 moles.

For Hydrogen  = \frac{18}{5.8}=3.10\approx 3

For Nitrogen = \frac{5.8}{5.8}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : N = 3 : 1

Hence, the empirical formula for the given compound is NH_3

3 0
3 years ago
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