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statuscvo [17]
2 years ago
11

Which is NOT a way to accelerate an object? *

Chemistry
1 answer:
olasank [31]2 years ago
4 0
Slow it down - I believe?
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QuODUUII IU VI<br> 2 Points<br> What is molarity?
Julli [10]

Answer:

Molarity is similar to Concentration

Explanation:

Molarity (M) is the amount of solute in a solvent, similar to concentration.

5 0
3 years ago
Read 2 more answers
If a gold bar is 16,000 g mass and 800 cm^3 volume what is the density?
ki77a [65]

Answer:

<h3>The answer is 20 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 16,000 g

volume = 800 cm³

We have

density =  \frac{16000}{800}  =  \frac{160}{8}  \\

We have the final answer as

<h3>20 g/cm³</h3>

Hope this helps you

5 0
3 years ago
According to the phase diagram for water, how is the state of water determined?
ad-work [718]
I believe it’s 2? Because it’s saying read the temperature. Which is basically saying look at what state the water is in. Ex: hot or cold
5 0
3 years ago
Read 2 more answers
ΚΕ:<br> m.22<br> 2<br> What is the kinetic energy of 10kg dog running with a velocity of 12m/s?
BigorU [14]

Answer:

The answer is

<h2>720 Joules</h2>

Explanation:

The kinetic energy of a body can be found by using the formula

<h3>K.E =  \frac{1}{2}  {mv}^{2}</h3>

where

m is the mass

v is the velocity / speed

From the question

mass = 10 kg

velocity = 12 m/s

Substitute the values into the above formula and solve

That's

<h3>KE =  \frac{1}{2}  \times 10 \times  {12}^{2}  \\   = 5 \times 144  \:  \:</h3>

We have the final answer as

<h3>720 Joules</h3>

Hope this helps you

3 0
3 years ago
How to do limiting reagents for chemistry?
gavmur [86]
Balance the chemical equation for the chemical reaction.
Convert the given information into moles.
Use stoichiometry for each individual reactant to find the mass of product produced.
The reactant that produces a lesser amount of product is the limiting reagent.
The reactant that produces a larger amount of product is the excess reagent.
To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.
4 0
3 years ago
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