Helium decays to form lithium
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In ground-state electron configuration, the<u> principal quantum number</u> (n), <u>the orbital</u> (s, p, d, or f), and the total number of <u>electrons</u> are used to represent electron configurations.
Case 1 Ground-state electron configuration of elements.
A) Chlorine: 1s²2s²23s²3
B) Cesium: 1s² 2s²2p⁶ 3s²3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 6s¹
C) Vanadium: 1s²2s²2p⁶3s²3p⁶3d³4s²
D) Rhenium: 1s² 2s² 2p⁶ 3s² 3p⁶3d¹⁰ 4s²4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁵ 6s²
Case 2 : Number of valence electron in atoms
A) Sn -Tin - Four valence electrons
B) La - Lanthanum - Three valence electrons
C) Mn - Manganese - Seven valence electrons
D) Zn- Zinc - Two valence electrons
Case 3 Ground-state electronic configuration of ions
A) Co⁺³ : 1s² 2s² 2p⁶ 3s² 3p⁶4s¹3d⁵
B) Mo⁺² : 1s² 2s² 2p⁶3s²3p⁶ 4s² 3d¹⁰ 4p⁶5s² 4d²
C) Ra⁺² : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 4f¹⁴ 5s² 5p⁶ 5d¹⁰ 6s² 6p⁶
D) I⁻ : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶
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Detonation of nitroglycerin:
<span>Mass nitroglycerin = 2.00 mL x 1.592 g/mL = 3.184 g
</span>
Moles = mass / molar mass = 3.184<span> g/ 227.0872 g/mol = 0.01402
</span>
the ratio between nitroglycerin and Carbon dioxide is 4 : 12
So, moles CO2 = 0.01402 x 12 / 4 =0.0420
the ratio between nitroglycerin and N2 is 4 : 6
moles N2 = 0.01402 x 6 / 4 =0.0841
<span>the ratio between nitroglycerin and O2 is 4 : 1 </span>
moles O2 = 0.01402 x 1 / 4 = 0.0035
<span>the ratio between nitroglycerin and water is 4 : 1 </span>
<span>in the same way moles water = 0.005258 </span>
total moles = 0.0420 + 0.0841 + 0.0035 + 0.005258 = 0.130758
0.130758<span> x 55 = 5.78 L </span>
Mass N2 = 0.0841 mol x 28.0134 g/mol = 2.3548 g
<span>Mass nitroglycerin = 2.00 mL x 1.592 g/mL = 3.184 g
</span>
Moles = mass / molar mass = 3.184<span> g/ 227.0872 g/mol = 0.01402
</span>
the ratio between nitroglycerin and Carbon dioxide is 4 : 12
So, moles CO2 = 0.01402 x 12 / 4 =0.0420
the ratio between nitroglycerin and N2 is 4 : 6
moles N2 = 0.01402 x 6 / 4 =0.0841
<span>the ratio between nitroglycerin and O2 is 4 : 1 </span>
moles O2 = 0.01402 x 1 / 4 = 0.0035
<span>the ratio between nitroglycerin and water is 4 : 1 </span>
<span>in the same way moles water = 0.005258 </span>
total moles = 0.0420 + 0.0841 + 0.0035 + 0.005258 = 0.130758
0.130758<span> x 55 = 5.78 L </span>
Mass N2 = 0.0841 mol x 28.0134 g/mol = 2.3548 g