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3 years ago

Will someone PLEASEEEE help me find the coordinates to these !

Mathematics

1 answer:

Xelga [282]3 years ago

3 0

Answer:

883037%

Step-by-step explanation:

i thank thats the we way we did it i am not shure

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Avery spent 170 minutes outside. If

tiny-mole [99]

Answer:

58 minutes

Step-by-step explanation:

s = 170 - 64 - 48

s = 58

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3 years ago

Read 2 more answers

Write in slope intercept form.<br> 15x − 4y = 11

kvv77 [185]

Answer:

y = 15/4x - 11/4

Step-by-step explanation:

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3 years ago

#10) What is the rate of change of y with

frez [133]

Answer:

#10) What is the rate of change of y with

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3 years ago

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$

$p = 22$

The pentagon MNPQR has a perimeter of 22 units.

4 0

3 years ago

Assume that AGHIE ALMN. Which of the following congruence statements

vladimir1956 [14]

answers below

so you guys won’t get it wrong

7 0

2 years ago