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Lynna [10]
3 years ago
7

Will someone PLEASEEEE help me find the coordinates to these !

Mathematics
1 answer:
Xelga [282]3 years ago
3 0

Answer:

883037%

Step-by-step explanation:

i thank thats the we way we did it i am not shure

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Is y = -4 + 2x linear?​
BlackZzzverrR [31]

Answer: it is linear

Step-by-step explanation: Find the degree of the equation to determine if linear.

5 0
2 years ago
Read 2 more answers
Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]

The left and right endpoints of the i-th subinterval, respectively, are

\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8

r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8

for 1\le i\le4, and the respective midpoints are

m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8

  • Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}

  • Midpoint rule

We approximate the area for each subinterval by

M_i=f(m_i)(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}

  • Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial p_i(x), where

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It so happens that the integral of p_i(x) reduces nicely to the form you're probably more familiar with,

S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))

Then the integral is approximately

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0
3 years ago
I NEED this answered right NOW please!!!!​
kykrilka [37]
Don’t click the link-
7 0
2 years ago
Read 2 more answers
Is an Obtuse triangle a Acute triangle? Yes or no? And why or why not?
777dan777 [17]

Answer:

No, this is because the word obtuse is in the name obtuse triangle as well as it being a whole different angle than an acute angle. Obtuse angles are are greater than 90 degress but less than 180 while the acute angle is less than 90.

Step-by-step explanation:

5 0
3 years ago
Evaluate b^2 c^-1 for b = -4 and c = 2.
Burka [1]

Answer:

8

Step-by-step explanation:

b^2 c^-1

Let b=-4 and c =2

(-4)^2 * (2)^-1

The negative exponent means it is in the denominator

(-4)^2 / (2)^1

16/2

8

4 0
3 years ago
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