Answer:
0.10 M AlCl₃.
Explanation:
We can calculate the concentration of chloride ion [Cl⁻] in each salt:
MgCl₂ is dissociated according to the reaction:
<em>MgCl₂ → Mg²⁺ + 2Cl⁻,</em>
Every 1 mol of MgCl₂ produces 2 mol of Cl⁻.
So, [Cl⁻] = (2)*(0.1 M) = 0.2 M.
AlCl₃ is dissociated according to the reaction:
AlCl₃ → Al³⁺ + 3Cl⁻,
Every 1 mol of AlCl₃ produces 3 mol of Cl⁻.
So, [Cl⁻] = (3)*(0.1 M) = 0.3 M.
CaCl₂ is dissociated according to the reaction:
CaCl₂ → Ca²⁺ + 2Cl⁻,
Every 1 mol of CaCl₂ produces 2 mol of Cl⁻.
So, [Cl⁻] = (2)*(0.05 M) = 0.1 M.
LiCl is dissociated according to the reaction:
LiCl → Li⁺ + Cl⁻,
Every 1 mol of LiCl produces 1 mol of Cl⁻.
So, [Cl⁻] = (1)*(0.1 M) = 0.1 M.
<em>So, the solution will have the highest concentration of chloride ions is </em><em>AlCl₃.</em>