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Andrej [43]
3 years ago
13

What is the surprising thing that happens in a superconductor?

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
8 0
With almost all substances . . .

-- when you cool them, their electrical resistance decreases.
-- If you make them even colder, their resistance decreases more.
-- If you make them even colder, their resistance decreases more.
-- If you make them even colder, their resistance decreases more.

-- If you keep making them colder, their resistance keeps decreasing,
but it never completely disappears, no matter how cold you make them.


But with a few surprising substances, called 'superconductors' . . .

-- when you cool them, their electrical resistance decreases.
-- If you make them even colder, their resistance decreases more.
-- If you make them even colder, their resistance decreases more.
-- If you make them even colder, their resistance decreases more.

-- If you keep making them colder, then suddenly, at some magic 
temperature, their resistance COMPLETELY disappears.  It doesn't 
just become small, and it doesn't just become too small to measure.  
It becomes literally totally and absolutely ZERO.  

If you start a current flowing in a superconducting wire, for example, 
you can connect  the ends of the wire together, and the current keeps 
flowing around and around in it, for months or years.  As long as you 
keep the loop cold enough, the current never decreases, because
the superconducting wire has totally ZERO resistance.

Did somebody say "What's this good for ?  What can you do with it ?"

1).  Every CT-scan machine and every MRI machine needs many 
powerful magnets to do its thing.  They are all electromagnets, with 
coils of superconducting wire, enclosed in containers full of liquid helium.  
Yes, it's complicated and expensive.  But it turns out to be simpler and 
cheaper than using regular electromagnets, with coils of regular plain
old copper wire, AND the big power supplies that would be needed
to keep them going.

2).  Resistance in wire means that when current flows through it,
energy is lost.  The long cables from the power-generating station
to your house have resistance, so energy is lost on the way from the
generating station to your house.  That lost energy is energy that the
electric company can't sell, because they can't deliver it to customers.

There are plans to build superconducting cables to carry electric power
from the producers to the customers.  The cables will be hollow pipes,
with liquid helium or liquid hydrogen inside to keep them cold, and 
something on the outside to insulate them from the warmth outside.
Yes, they'll be complicated and expensive.  But they'll have ZERO
resistance, so NO energy will be lost on its way from the generating 
stations to the customers.  The power companies think they can
build superconducting 'transmission lines' that will cost less than
the energy that's being lost now, with regular cables.
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Georgia [21]

Answer:

2 elements and one compund i think

Explanation:

4 0
3 years ago
19)Calculate the number of moles of Al2O3 that are produced when 15 mol of Fe is produced
Margarita [4]

Answer:

C

Explanation:

Calculate the number of moles of Al2O3 that are produced when 15 mol of Fe is produced

in the following reaction.

C) 45 mol

6 0
3 years ago
What is the limiting reactant for the following balanced equation when 9 moles of AlF3 are mixed with 12 miles of O2?
tamaranim1 [39]
<h2>Answer:AlF_{3} </h2>

Explanation:

The chemical equation of the reaction that occurs when AlF_{3} reacts with O_{2} is

4AlF_{3}+3O_{2}→2Al_{2}O_{3}+6F_{2}

4 moles of AlF_{3} requires 3 moles of O_{2}.

1 mole of AlF_{3} requires \frac{3}{4} moles of O_{2}.

Given that we have 9 moles of AlF_{3}.

9 moles of AlF_{3} requires \frac{3}{4}\times 9=6.75 moles of O_{2}.

But we have 12 moles of O_{2}.

So,AlF_{3}  will be consumed first.

So,AlF_{3}  is the limiting reagent.

3 0
3 years ago
Using the standard reduction potentials, Pb 2+(aq) + 2e– =&gt; Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– =&gt; Fe(s), E° = –0.44 V Zn
mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}

Fe(s) and Zn(s) will reduce Cr^{3+} to Cr

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with E_{red}^{0} value lower than 1.51 V will donate electron to Mn^{3+} and thus reduces Mn^{3+} to Mn^{2+}.

So, Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}.

Metal with E_{red}^{0} value lower than -0.40 V will donate electron to Cr^{3+} and thus reduces Cr^{3+} to Cr.

So, Fe(s) and Zn(s) will reduce Cr^{3+} to Cr.

6 0
3 years ago
Match the following vocabulary words.
Arada [10]

Answer:

4 line graph

5 pictograph

10 vertical axis

2 bar graph

8 axis

3 pie chart

6 dependent variable

9 horizontal axis

1 graph

3 independent variable

Explanation:

Can I please have brainliest ;)

5 0
3 years ago
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