Answer:
First step would be convert to moles
Final Answer: 37.8 g of NaCl
Explanation:
The reaction is:
2Na + Cl₂ → 2NaCI
We convert the mass of each reactant to moles:
18 g . 1mol /23g = 0.783 moles of Na
23g . 1mol / 70.9g = 0.324 moles of chlorine
We use the mole ratio to determine the limiting reactant:
Ratio is 2:1. 2 moles of Na react to 1 mol of chlorine
Then, 0.783 moles of Na, may react to (0.783 . 1)/2 = 0.391 moles.
Excellent!. We need 0.391 moles of Cl₂ and we only have 0.324 moles available. That's why the Cl₂ is our limiting reactant.
We use the mole ratio again, with the product side. (1:2)
1 mol of Cl₂ can produce 2 moles of NaCl
Then, our 0.324 moles of gas, may produce (0.324 . 2)/1 = 0.648 moles
Finally, we convert the moles to grams:
0.648 mol . 58.45g/mol =
H- is the one without electron
Do DIMENSIONAL Analysis what comes up must come down
Answer:
Explanation:
When determining empirical formulas of hydrates we have to find the mass of water which left the hydrate when heating The sample. This amount of water calculated will provide us with the correct ratio of moles water / moles anhydrate since moles water > moles anhydrate. The mistake might have been done while determining the water that left the sample so then we see and impropre result in ratios.
