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Elza [17]
3 years ago
13

Evaluate the expression below when x = -2. x2 − 8 x + 6

Mathematics
2 answers:
Katarina [22]3 years ago
6 0
(-2)²-8(-2)+6=4+16+6=26.
nordsb [41]3 years ago
3 0
Solve for x over the real numbers:x = -2. x^2 - 8 x + 6
Hint: | Rewrite the right hand side of the equation.-2. x^2 - 8 x + 6 = -2 x^2 - 8 x + 6:x = -2 x^2 - 8 x + 6
Hint: | Move everything to the left hand side.Subtract -2 x^2 - 8 x + 6 from both sides:2 x^2 + 9 x - 6 = 0
Hint: | Write the quadratic equation in standard form.Divide both sides by 2:x^2 + (9 x)/2 - 3 = 0
Hint: | Solve the quadratic equation by completing the square.Add 3 to both sides:x^2 + (9 x)/2 = 3
Hint: | Take one half of the coefficient of x and square it, then add it to both sides.Add 81/16 to both sides:x^2 + (9 x)/2 + 81/16 = 129/16
Hint: | Factor the left hand side.Write the left hand side as a square:(x + 9/4)^2 = 129/16
Hint: | Eliminate the exponent on the left hand side.Take the square root of both sides:x + 9/4 = sqrt(129)/4 or x + 9/4 = -sqrt(129)/4
Hint: | Look at the first equation: Solve for x.Subtract 9/4 from both sides:x = sqrt(129)/4 - 9/4 or x + 9/4 = -sqrt(129)/4
Hint: | Look at the second equation: Solve for x.Subtract 9/4 from both sides:Answer:  x = sqrt(129)/4 - 9/4 or x = -9/4 - sqrt(129)/4
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Step-by-step explanation of the

(-10)/(-20)

-1/(-2)

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1/2; c

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The length of a rectangle is 5 centimeters less than twice its width. The perimeter of the rectangle is 26 cm. What are the dime
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Let w and l be the length and height of the rectangle.

We know that:

\begin{cases}l = 2w-5\\2(l+w)=26\end{cases}

Substitute the first equation in the second:

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The following proportion could be used to change from feet to which measure.
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Step-by-step explanation:

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In a class of 100 students, 25 have hardcover and 75 students have paperback textbooks. If you randomly choose 15 students in th
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Answer:

23.72% probability that 3 of them have hardcover texts.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the students are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

If you randomly choose 15 students in this class, find the probability that 3 of them have hardcover texts.

Desired outcomes:

3 with hardcover texts, from a set of 25.

15-3 = 12 with paperback texts, from a set of 75. So

D = C_{25,3}*C_{75,12} = \frac{25!}{3!(22)!}*\frac{75!}{12!(63)!} = 6 \times 10^{16}

Total outcomes:

15 students from a set of 100. So

T = C_{100,15} = \frac{100!}{15!85!} = 2.53 \times 10^{17}

Probability:

P = \frac{D}{T} = \frac{6 \times 10^{16}}{2.53 \times 10^{17}} = 0.2372

23.72% probability that 3 of them have hardcover texts.

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3 years ago
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