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ArbitrLikvidat [17]
3 years ago
8

Draw two different shapes with a perimeter of 16 units. What is the area of each shape?

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
8 0

<u>Shape #1:  A square.</u> 
Every side is  4  units long. 
The perimeter is  16  units.
The area is  <em>16  </em>square units.

<u>Shape #2:  A rectangle.</u>
The length is  7.9  units.
The width is  0.1  unit.
The perimeter is  16  units.
The area is  <em>0.79</em>  of a square unit.

<u>Shape #3:  A circle.</u>
The diameter is  (16/π)  units.  (about  5.093  units)
The perimeter (circumference) is 16 units.
The area is  (64/π)  square units.          (about  <em>20.37</em>  square units)


frosja888 [35]3 years ago
5 0
So, you will obviously have to do the drawing bit, but I can help with the rest. I would first recommend drawing a square with a side length of 4, which will give you a perimeter of 16. The formula for area in a square is s², where s is the side length. That means the area for the square is 4², or 16 units², just like the perimeter.

You can draw any shape you like for the second one, but I would suggest a rectangle with a length of 6 and a width of 2. Perimeter for a rectangle is P = 2L + 2w , and 2(6) +2(2) = 16. The area would then be the length times the width, or 2(6), which equals 12 units² for the second figure.
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Answer:

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Step-by-step explanation:

So, this is a simple factoring problem. The answer is 5.5(2x-1). So, heres how we get that answer.

So, factoring is basically breaking down the problem into smaller parts. So once we simplify the problem, we can factor it.

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tensa zangetsu [6.8K]

Answer: 1  1/18

Step-by-step explanation: 5/6 + 2/9 I know this might seem like common, but <em>the </em><em>Numerator is the top number of a fraction</em><em> and the </em><em>Denominator is the bottom a fraction.</em> When the numerator and the denominator are the same such as 5/5 the fraction equals one (I know its real fancy). When you're multiplying a fraction that equals on by another fraction its really just multiplying by a fancy looking 1 that's disguised as a fraction such as  5/5. If you simplify it it goes to the fraction it was as long it was simplified to the max  (5/5 x 1/2 = 5/10= 1/2)

  • First, you need to find a like denominator,  which is 18
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3 years ago
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snow_lady [41]
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3 0
3 years ago
(GIVING BRAINLIEST!!)
Bogdan [553]

Answer:

Solution :-

On first day, Ingrid dug eighteen twentieth of a meter = (18/20) of 1 meter = (18/20) * 1 = (9/10) meters .

Now,

→ Next day, Ingrid dug nine twentieth of a mater = (9/20) of 1 meter = (9/20) * 1 = (9/20) meters .

So,

→ Total length of the trench = Ingrid dug in first day + Ingrid dug next day = (9/10) + (9/20) = (9*2 + 9)/20 = (18 + 9)/20 = (27/20) = 1.35 meters.

Therefore,

→ Total length of the trench = 1.35m ≈ 1.00 meter .

Hence, a reasonable estimate of the total length of the trench is 1.00 meter.

so, b

Step-by-step explanation:

3 0
3 years ago
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