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ArbitrLikvidat [17]
3 years ago
8

Draw two different shapes with a perimeter of 16 units. What is the area of each shape?

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
8 0

<u>Shape #1:  A square.</u> 
Every side is  4  units long. 
The perimeter is  16  units.
The area is  <em>16  </em>square units.

<u>Shape #2:  A rectangle.</u>
The length is  7.9  units.
The width is  0.1  unit.
The perimeter is  16  units.
The area is  <em>0.79</em>  of a square unit.

<u>Shape #3:  A circle.</u>
The diameter is  (16/π)  units.  (about  5.093  units)
The perimeter (circumference) is 16 units.
The area is  (64/π)  square units.          (about  <em>20.37</em>  square units)


frosja888 [35]3 years ago
5 0
So, you will obviously have to do the drawing bit, but I can help with the rest. I would first recommend drawing a square with a side length of 4, which will give you a perimeter of 16. The formula for area in a square is s², where s is the side length. That means the area for the square is 4², or 16 units², just like the perimeter.

You can draw any shape you like for the second one, but I would suggest a rectangle with a length of 6 and a width of 2. Perimeter for a rectangle is P = 2L + 2w , and 2(6) +2(2) = 16. The area would then be the length times the width, or 2(6), which equals 12 units² for the second figure.
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A blueprint for a building includes a rectangular room that measures 3 inches long and 5.5 inches wide. The scale for the bluepr
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Answer:

30 ft. x 55ft

Step-by-step explanation:

3 x 5.5

1 inch = 10 ft

3 * 10 = 30

5.5 = 55

30' x 55'

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How much must be added to each of the three numbers 1, 11, and 23 so that together they form a geometric progression?
Sliva [168]

Answer:

49

Step-by-step explanation:

Let x be unknown number which should be added to numbers 1, 11, 23 to get geometric progression. Then numbers 1 + x, 11 + x, 23 + x are first three terms of geometric progression.

Hence,

b_1=1+x\\ \\b_2=11+x\\ \\b_3=23+x

and

b_2=b_1\cdot q\Rightarrow 11+x=(1+x)q\\ \\b_3=b_2\cdot q\Rightarrow 23+x=(11+x)q

Express q:

q=\dfrac{11+x}{1+x}=\dfrac{23+x}{11+x}

Solve this equation. Cross multiply:

(11+x)^2=(1+x)(23+x)\\ \\121+22x+x^2=23+x+23x+x^2\\ \\121+22x=23+24x\\ \\22x-24x=23-121\\ \\-2x=-98\\ \\2x=98\\ \\x=49

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3 years ago
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Kitty [74]

Answer:

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Plz, help!!!!! 15 pts
Korolek [52]

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Which of the following is a polynomial with roots: − square root of 5 , square root of 5 , and −3?
tresset_1 [31]
Roots: - √5 , √5, and - 3

=> these are factors of the polynomial: (x + √5), (x - √5), and (x + 3).

Multiply those three factors:

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Answer: option B. x^3 + 3x^2 - 5x - 15
4 0
3 years ago
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