Acceleration= velocity/time
1.1/2.7=0.41
The acceleration is .41 m/s^2
(any unit of mass) x (any unit of speed) is a unit of momentum.
The only choice on the list with the dimensions of (mass) x (speed)
is 'c'.
'a' is a unit of force.
'b' is meaningless.
'c' is a false statement.
(a)
consider the motion of the tennis ball. lets assume the velocity of the tennis ball going towards the racket as positive and velocity of tennis ball going away from the racket as negative.
m = mass of the tennis ball = 60 g = 0.060 kg
v₀ = initial velocity of the tennis ball before being hit by racket = 20 m/s
v = final velocity of the tennis ball after being hit by racket = - 39 m/s
ΔP = change in momentum of the ball
change in momentum of the ball is given as
ΔP = m (v - v₀)
inserting the above values
ΔP = (0.060) (- 39 - 20)
ΔP = - 3.54 kgm/s
hence , magnitude of change in momentum : 3.54 kgm/s
Answer:
A. 260 mm
B. - 18
C. 175
Explanation:
A
The expression for the lens equation is
v = 259 mm
= 260 mm or 26 cm (to 2 s.f)
check the attached files for additional solution
Answer:
7.92 m/s
Explanation:
= Mass of raindrop = 
= Mass of mosquito
= Initial Velocity of raindrop = 8.1 m/s
= Initial Velocity of mosquito = 0 m/s
= Velocity of center of mass
For elastic collision
Hence, the velocity of the attached mosquito, falling immediately afterward is 7.92 m/s
