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lozanna [386]
3 years ago
5

The unit for momentum is which of the following?

Physics
1 answer:
Alika [10]3 years ago
6 0

(any unit of mass) x (any unit of speed)  is a unit of momentum.

The only choice on the list with the dimensions of (mass) x (speed)
is 'c'.

'a' is a unit of force.
'b' is meaningless.
'c' is a false statement.
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Answer all of these questions and you will get the brain list
krek1111 [17]

Answer:

<em>I</em><em> </em><em>hope this</em><em> </em><em>helps</em><em> </em>

Explanation:

1. 10×3 = 30N

2. 5×1.2 = 6N

3. 3/6= 0.5m/s²

6 0
3 years ago
For a satellite to be in a circular orbit 950 km above the surface of the earth, what orbital speed must it be given?
ANTONII [103]

1.) 7382 m/s

The gravitational attraction between the satellite and the Earth provides the centripetal force that keeps the satellite in circular motion, so we can write

\frac{GMm}{(R+h)^2}=m\frac{v^2}{R+h}

where

G is the gravitational constant

M=5.98\cdot 10^{24}kg is the Earth's mass

m is the satellite's mass

R=6370 km = 6.37\cdot 10^6 m is the Earth's radius

h=950 km = 0.95\cdot 10^6 m is the altitude of the satellite above the Earth's surface

v is the orbital speed

Solving the formula for v, we find

v=\sqrt{\frac{GM}{R+h}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24} kg)}{(6.37\cdot 10^6 m +0.95\cdot 10^6 m)}}=7382 m/s

2) 1.73 hours

The period of the orbit is the time taken to complete one revolution around the Earth, therefore:

T=\frac{2\pi (R+h)}{v}

where the numerator is the circumference of the orbit and v the orbital speed, therefore we find

T=\frac{2\pi (6.37\cdot 10^6 m+0.95e6 m)}{7382 m/s}=6227 s

Converting into hours,

T=\frac{6227 s}{3600 s/h}=1.73 h

6 0
3 years ago
An object takes 2.8 years to orbit the Sun. What is its average distance (in AU) from the Sun?
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answer look it up

Explanation:https://www.chegg.com/homework-help/questions-and-answers/takes-planet-28-years-orbit-sun-long-years-take-planet-go-way-around-sky-q29849397

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3 years ago
For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg
jeyben [28]

Answer:

<h2>Magnetic field strength in that region is 1.2 T</h2>

Explanation:

As we know by the formula of radius of charge moving in external field is given as

R = \frac{mv}{qB}

so we will have

R = 25 cm

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now we have

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semiconductors ... silicon, germanium etc ...

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