A body of mass 2.9 kg is suspended from a string of length 2.5 metres and is at rest. A bullet of mass 100 gram moving horizonta
lly with a speed of 150 metres per second strikes and sticks to it. what is the maximum angle made by the string with vertical after the impact.
(g=10m/s)
(g=10m/s)
1 answer:
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To solve this problem it is necessary to apply the kinematic equations of motion.
By definition we know that the position of a body is given by
Where
Initial position
Initial velocity
a = Acceleration
t= time
And the velocity can be expressed as,
Where,
For our case we have that there is neither initial position nor initial velocity, then
With our values we have , rearranging to find a,
Therefore the final velocity would be
Therefore the final velocity is 81.14m/s
Answer:
Part a)
Part b)
Explanation:
Part a)
Level of sound = 75 dB
now we know that
here we know that
now we have
Part b)
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here we know that
so we have
now we know
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