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Klio2033 [76]
3 years ago
14

A body of mass 2.9 kg is suspended from a string of length 2.5 metres and is at rest. A bullet of mass 100 gram moving horizonta

lly with a speed of 150 metres per second strikes and sticks to it. what is the maximum angle made by the string with vertical after the impact.
(g=10m/s)​

Physics
1 answer:
givi [52]3 years ago
6 0

Heres your answer to ur question

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If you can answer both, please do. But if you can't, just answer one.
Setler [38]

Answer:

1.The force required to stop the shopping cart is, F = 12.25 N

Explanation:

Given data,

The mass of the shopping cart, m = 7 kg

The initial velocity of the shopping cart, u = 3.5 m/s

The final velocity of the shopping cart, v = 0 m/s

The time period of acceleration, t = 2 s

The change in momentum of the cart,

                                      p = m(u - v)

                                         = 7 (3.5 - 0)

                                         = 24.5 kg m/s

The force is defined as the rate of change of momentum. To stop the shopping cart, the force required is given by the formula

                                           F = p / t

                                               = 24.5 / 2

                                               = 12.25 N

Hence, the force required to stop the shopping cart is, F = 12.25 N

2.

We have: F = m × v/t

Here, m = 8500 Kg

v = 20 m/s

t = 10 s

Substitute their values into the expression,  

F = 8500 × 20/10

F = 8500 × 2

F = 17000 N

In short, final answer would be 17000 N

Hope this helps!!

7 0
3 years ago
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