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3 years ago

Which of the following are units that can be used to describe vector

Physics

2 answers:

In-s [12.5K]3 years ago

7 0

The answer is D ! Hope this helps !

rewona [7]3 years ago

3 0

The answer is D because it’s going by the miles

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Could a mixture be made up of only elements and no compounds. if so explain

Irina18 [472]

I racked my brain for almost 10 minutes, until suddenly,
it hit me !

You're breathing one right now ! So am I .

Air is a mixture of a lot of elements.
Nitrogen, Oxygen, and Argon account for 99.964 percent.

The other 0.036 percent is mainly Neon, Helium, Krypton,
and Hydrogen ... more elements.

Then there are Carbon Dioxide and water vapor.
Yes, those are compounds. But together, they add up
to very little of the air we breathe, and if both of them
suddenly disappeared, we would hardly notice it.

7 0

3 years ago

A jet aircraft with mass of 658,055 kilograms is flying straight downward. At an instant the plane's engine is producing an down

sdas [7]

Answer:

The acceleration of the plane is 10.93 m/s² at that instant.

Explanation:

Given:

Mass of aircraft, $m=658055\textrm{ kg}$

Downward thrust produced, $F=1484732.5\textrm{ N}$

Upward resistance force by air, $F_{R}=740492.6\textrm{ N}$

Weight of the aircraft acting donward, $W=mg=658055\times 9.8=6448939\textrm{ N}$

According to Newton's second law, net force acting on an object is equal to the product of mass and its acceleration.

Here, the net force is given as the difference of downward forces and upward forces.

$F_{net}= F+W-F_{R}\\ F_{net}=1484732.5+6448939-740492.6=7193178.9\textrm{ N}$

Now,

$F_{net}=ma\\7193178.9=658055a\\a=\frac{7193178.9}{658055}=10.93\textrm{ }m/s^{2}$

Therefore, the acceleration of the plane is 10.93 m/s² at that instant.

3 0

3 years ago

A narrow copper wire of length L and radius b is attached to a wide copper wire of length L and radius 2b, forming one long wire

Morgarella [4.7K]

Answer:

electric field in the wide wire is

E₂ = $\frac{E}{4}$

Explanation:

given

length of the copper wire = L

radius of the copper wire r₁ = b

length of the second copper wire = L

radius of the second copper wire r₂ = 2b

electric field in the narrow wire = E₁=E

recall

resistance R = ρL/A

where ρ is resistivity of the copper wire, L is the length, and A is the cross sectional area.

Resistance of narrow wire, R₁

R₁ = ρL/A

where A = πb²

R₁ = ρL/πb²---------- eqn 1

Resistance of wide wire, R₂

R₂ = ρL/A

where A = π(2b)²

R₂ = ρL/π(2b)²

R₂ = ρL/4πb²-------------- eqn 2

R₂ = ¹/₄(ρL/πb²)

comparing eqn 1 and 2

R₁ = 4R₂

calculating the current in the wire,

I = E/(R₁ + R₂)

recall

R₁ = 4R₂

∴ I = E/(4R₂ + R₂)

I = E/5R₂

calculating the potential difference across R₁ & R₂

V₁ = IR₁

I = E/5R₂

∴ V₁ = ER₁/5R₂

R₁ = 4R₂

V₁ = 4ER₂/5R₂

∴V₁ = ⁴/₅E

potential difference for R₂

V₂= IR₂

I = E/5R₂

∴ V₂ = ER₂/5R₂

V₂ = ER₂/5R₂

∴V₂ = ¹/₅E

so, electric field E = V/L

for narrow wire E₁ = V₁/L ----------- eqn 3

for wide wire, E₂ = V₂/L------------ eqn 4

compare eqn 3 and 4

E₂/E₁ = V₂/V₁( L is constant)

E₂/E₁ = ¹/₅E/⁴/₅E

E₂ = E₁/4

note E₁ = E

∴E₂ = $\frac{E}{4}$

8 0

4 years ago

Describe how positive and negatives pairs will react?

oksian1 [2.3K]

Positive will react better together. But opposites will try to get as far away as possible.

6 0

3 years ago

A monochromatic light of wavelength 506 nm from a distant source is incident on a single slit 0.075 mm wide. Diffraction pattern

sladkih [1.3K]

Answer:

first minimum distance from the center = 0.417 m m

Explanation:

given,

wavelength (λ) = 506 nm

d = 0.075 mm = 0.000075 m

tanθ = x /2

d sinθ = m λ

m=1 ( 1 st minimum )

0.000075 × sin θ = 506 × 10⁻⁹

sin θ = $\dfrac{506 × 10⁻⁹}{0.000075}$

sin θ = 0.00675

θ = sin⁻¹(0.00675)

θ = 0.00675

x = 0.000417 m

hence, the first minimum distance from the center = 0.417 m m

5 0

3 years ago