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kolbaska11 [484]
2 years ago
14

Please check my answers!

Physics
2 answers:
Alecsey [184]2 years ago
8 0
A.) The higher the altitude, the colder the climate will be

B.) Areas near the equator have warmer climates than areas for form the equator.

D.) Winds that blow inland from oceans or large lakes contain a lot of water vapor that will cause precipitation.

C.) Monsoons.
nekit [7.7K]2 years ago
8 0

Answer:

A)  The higher the altitude, the colder the climate will be

B) Areas near the equator have warmer climates than areas for form the equator.

D) Winds that blow inland from oceans or large lakes contain a lot of water vapor that will cause precipitation.

C.) Monsoons.

Explanation:

1)

The climate is the result of the behavior of the different elements such as rainfall, temperature, atmospheric pressure, winds and humidity. The behavior of these elements is determined by the factors involved in each zone. One of those factors is the altitude, which is the height of the ground of a place with respect to sea level.

The altitude influences so that at a higher altitude there is a decrease in temperatures, therefore at a higher altitude the climate will be much colder. This happens because the atmosphere is heated from the ground upwards since solar energy is radiated from the earth's surface. Then the further you are from the surface, the colder the place will be. In addition, the atmospheric pressure in high places is low, which means that the air molecules move more slowly and causes the temperatures to decrease.

2)

Another factor that influences the climate is latitude, which is the distance from a point on Earth to Ecuador, which is where the warmest areas are. This is related to the incidence of solar rays. The areas closest to Ecuador receive the sun's rays more intensely. The areas near the poles, in addition to not receiving the sun's rays perpendicularly, are illuminated only for part of the year.

3)

Wind is the movement of air that travels from high pressure to low pressure areas. The air constantly travels horizontally in the atmosphere, raising hot air masses, and when the humidity of the air exceeds the saturation point it condenses to fall as precipitation.

In times of heat, water absorbs large amounts of energy. The evaporation process is very intense, which causes the air temperature to be reduced.During the cold seasons, on the contrary, the heat accumulated in the sea water is released. This process makes the relative humidity of the air in the coastal areas higher than those of the interior of the continents.  

And this is manifested through the wind, which also in maritime areas or lakes can retain more humidity

4)

In winter the land is colder than the sea, therefore, the density and air pressure on the earth will be greater. As a result, the wind flows from land to sea. In summer the situation will reverse. The earth is warmer and the air above the earth is of lower density; The wind flows from sea to land. This produces the monsoons.

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Add these measurements, using significant digit rules:<br><br> 1.0090 cm + 0.02 cm = cm
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Answer:

1.029

Explanation:

1.0090 can also be looked at as "1.009"

0.02 can also be looked at as "0.020"

I think of it as 20+9 which is 29. There for your answer should be 1.029. There are no measurement rules applying to this equation since they are both in centimeters. So you don't have to convert anything.

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3 years ago
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Three point charges are placed on the y-axis: a charge q at y=a, a charge –2q at the origin, and a charge q at y= –a. Such an ar
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Answer:

electric field   Et = kq [1 / (x-a)² -2 / x² + 1 / (x+a)²]

Explanation:

The electric field is a vector, so it must be added as vectors, in this problem both the charges and the calculation point are on the same x-axis so we can work in a single dimension, remembering that the test charge is always positive whereby the direction of the field will depend on the load under analysis, if the field is positive, if the field is negative.

 a) Let's write the electric field for each charge and the total field

       E = k q /r

With k the Coulomb constant, q the charge and r the distance of the charge to the test point

       Et = E1 + E2 + E3

       E1 = k q / (x-a)²

       E2 = k (-2q) / x²  

       E3 = k q / (x + a)²

       Et = kq [1 / (x-a)² -2 / x² + 1 / (x+a)²]

The direction of the field is along the x axis

b) To use a binomial expansion we must have an expression the form (1-x)⁻ⁿ  where x << 1, for this we take factor like x from all the equations

       Et = kq/ x² [1 / (1-a/x)² - 2 + 1 / (1+a/x)²]

We use binomial expansion

     (1+x)⁻² = 1 -nx + n (n-1) 2! x² +… x << 1

     (1-x)⁻² = 1 +nx + n (n-1) 2! x² + ...

They replace in the total field and leaving only the first terms

       

   Et =kq/x² [-2 +(1 +2 a/x + 2 (2-1)/2 (a/x)² +…) + (1 -2 a/x + 2(2-1) /2 (a/x)² +.) ]

   Et = kq/x² [a²/x² + a²/x²2] = kq /x² [2 a²/x²]

Et = k q 2a²/x⁴

point charge

Et = k q 1/x²

Dipole

E = k q a/x³

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2 years ago
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I think their distance is a measurement of : B. space in two dimension

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3 years ago
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A roadway for stunt drivers is designed for racecars moving at a speed of 40 m/s. A curved section of the roadway is a circular
Fynjy0 [20]

Answer:

Bank angle = 35.34o

Explanation:

Since the road is frictionless,

Tan (bank angle) = V^2/r*g

Where V = speed of the racing car in m/s, r = radius of the arc in metres and g = acceleration due to gravity in m/s^2

Tan ( bank angle) = 40^2/(230*9.81)

Tan (bank angle) = 0.7091

Bank angle = tan inverse (0.7091)

Bank angle = 35.34o

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