<u>Answer:</u> The ball is travelling with a speed of 5.5 m/s after hitting the <u>bottle.</u>
<u>Explanation:</u>
To calculate the speed of ball after the collision, we use the equation of law of conservation of momentum, which is given by:

where,
are the mass, initial velocity and final velocity of ball.
are the mass, initial velocity and final velocity of bottle.
We are given:

Putting values in above equation, we get:

Hence, the ball is travelling with a speed of 5.5 m/s after hitting the bottle.
The same speed of light, the fastest possible
darkness is just the absence of light therefore once light leaves darkness returns. making darkness have the same speed of light
<u>Answer</u>
longitudinal wave because the particles move parallel to the direction that the wave is traveling.
<u>Explanation</u>
There are 2 types of a wave, electromagnetic and mechanical wave. These waves can also be categorized into two, longitudinal ans transverse waves.
longitudinal wave is a wave whose particles vibration is in the direction of wave travel.
Transverse wave is a wave whose vibration of particles is perpendicular to the direction of wave travel.
The total amount of energy stays the same, but throughout the ride, the kinetic energy and the potential energy change, still adding up to the same number. At the top of the ride it has potential energy, and as it goes down the potential energy decreases and the kinetic energy increases. When it’s at the bottom of the first drop it has maxed out its kinetic energy, and minimized its potential energy. Friction slows down the car, and pushes on the cart with a force that is equal and opposite to the force being exerted in the track. The reason the track keeps going is because though it exerts and equal and opposite force the momentum of the objects is different, allowing the car to continue moving, however friction will slow it down until eventually it comes to a stop.
Given data;
Fn = 10 N
Fs = 7 N
Fe = 4 N
force in X direction (Fx) = 4 N
force in Y direction (Fy) = 10-7 = 3 N
Net force (Fnet) = Sq.root[(Fx)² + (Fy)²]
= Sq root [ 4² + 3² ]
= 25 N
<em> Net force acting = 25 N</em>