The value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.
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Coefficient of the kinetic friction</h3>
The value of coefficient of kinetic friction is calculated as follows;
F - Ff = ma
F - μmgcosθ = ma
where;
- F is applied force
- μ is coefficient of kinetic friction
- m is mass of the wagon
- a is acceleration of the wagon
182 - μ(20 x 9.8 x cos30) = 20(2.5)
182 - 169.74μ = 50
182 - 50 = 169.74μ
132 = 169.74μ
μ = 132/169.74
μ = 0.78
Thus, the value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.
Learn more about coefficient of friction here: brainly.com/question/20241845
Answer:
e = 0.0898m
v = 2.07m/s
Explanation:
a) According to Hooke's law
F = ke
e is the extension
k is the spring constant
Since F = mg
mg = ke
e = mg/k
Substitute the given value
e = 1.1(9.8)/120
e = 10.78/120
e = 0.0898m
Hence it is stretched by 0.0898m from its unstrained length
2) Total Energy = PE+KE+Elastic potential
Total Energy = mgh +1/2mv²+1/2ke²
Substitute the given value
5.0= 1.1(9.8)(0.2)+1/2(1.1)v²+1/2(120)(0.0898)²
Solve for v
5.0 = 2.156+0.55v²+0.48338
5.0-2.156-0.48338= 0.55v²
2.36 =0.55v²
v² = 2.36/0.55
v² = 4.29
v ,= √4.29
v = 2.07m/s
Hence the required velocity is 9.28m/s
The amount of matter in an object is called its, mass. How much the mass weights would be referred to as weight
Answer:




Explanation:
r = Radius of disk = 7.9 cm
N = Number of revolution per minute = 1190 rev/minute
Angular speed is given by

The angular speed is 
r = 2.98 cm
Tangential speed is given by

Tangential speed at the required point is 
Radial acceleration is given by

The radial acceleration is
.
t = Time = 2.06 s
Distance traveled is given by

The total distance a point on the rim moves in the required time is
.