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3 years ago

Find the values for a and b that would make the following equation true.

Mathematics

2 answers:

ale4655 [162]3 years ago

4 0

Answer:

\left(ax^2\right)\left(-6x^b\right)=12x^5\\\\(-6a)x^{2+b}=12x^5\to -6a=12\ and\ 2+b=5\\\\-6a=12\ \ \ |:(-6)\\a=-2\\\\2+b=5\ \ \ |-2\\b=3

Answer:\ a=-2;\ b=3

Step-by-step explanation:

natali 33 [55]3 years ago

4 0

Answer:

a = - 2 and b = 3

Step-by-step explanation:

Expand the left side and compare relevant values to the right side

(ax²)(-6 $x^{b}$ ) = - 6a $x^{2+b}$

For the 2 sides to equate then

- 6a = 12 ⇒ a = - 2 and

2 + b = 5 ⇒ b = 5 - 2 = 3

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2 years ago

Which of the following is NOT a rational number?

makvit [3.9K]

Answer:

A rational number is a number that can be expressed as a fraction (the ratio of two integers).

Integer: A whole number that can be positive, negative, or zero.

To calculate if each radical can be expressed as a rational number, convert the decimals into rational numbers, then simplify:

$\sqrt{121}=\sqrt{11^2}=11=\dfrac{11}{1} \quad \leftarrow \textsf{rational}$

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1 year ago

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3 years ago

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