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Harrizon [31]
3 years ago
6

Yunika downloaded three applications for $2.99 each to her cell phone. The remaining applications that Yunika purchased cost $1.

99 each.
If she downloaded x total applications, which of the following equations can be used to find how much Yunika spent on cell phone application downloads?
Mathematics
2 answers:
777dan777 [17]3 years ago
7 0
You can formulate the equation below to work out your question:

3(2.99) + 1.99(x-3) 
8.97 + 1.99x - 5.97
1.99x + 3 

CHECK:
If x = 5
3 x 2.99 + 2 x 1.99 = 8.97 + 3.98 = 12.95
1.99 x 5 +3 = 12.95

Hope I helped.
Contact [7]3 years ago
7 0

Answer:

The answer is A. y = 1.99(x - 4) + 11.96

Step-by-step explanation:

I just took the quiz.

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GrogVix [38]

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45.5 ft sqaured

Step-by-step explanation:

5 0
2 years ago
What is the value of n in the relationship 8n+9=-n+5
vitfil [10]
Subtract 5 from both sides.

8n + 4 = -n

Subtract 8n from both sides.

4 = -9n

Divide both sides by -9 to solve for n.

- \frac{4}{9} = n

The value of n is -4/9.
8 0
3 years ago
1. Fifty-eight thousandths
kap26 [50]

fifty-eight thousandths?

4 0
3 years ago
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 75 type K batteries and a sample of 46
lorasvet [3.4K]

The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

H_1: \mu_1 - \mu_2 \neq 0

We have a two-tailed test, as we are testing if the mean is different of a value.

Considering the significance level of 0.05, with 75 + 46 - 2 = 119 df, the critical value for the test is given as follows:

|t| = 1.9801.

Hence the decision rule is:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

More can be learned about the t-distribution in the test of an hypothesis at brainly.com/question/13873630

#SPJ1

3 0
1 year ago
For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =
enyata [817]
Given that <span>For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d=v+\frac{v^2}{20}, where [tex]d is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

v+ \frac{v^2}{20} \leq75 \\  \\ 20v+v^2\leq1,500 \\  \\ v^2+20v+100\leq1,500+100 \\  \\ (v+10)^2\leq1,600 \\  \\ |v+10|\leq\sqrt{1,600} \\  \\ -40\leq v+10\leq40 \\  \\ -40-10\leqv\leq v\leq40-10 \\  \\ -50\leq v\leq30

Therefore, the range of speed she can travel is v\leq30\ mi/hr
</span>
8 0
3 years ago
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