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weeeeeb [17]
3 years ago
15

One factor of x^3-3x^2-4x+12 is x+2. find the remaining factors

Physics
1 answer:
telo118 [61]3 years ago
6 0
Dividing  x^3 - 3x^2 - 4x + 12 by x + 2 gives

x^2 -5x + 6

= (x - 3)(x - 2)

so remaining factors are    x - 3 and x - 2 answer
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Sugar is made of carbon, hydrogen, and oxygen atoms. Sugar is
Aneli [31]
D. A solution because it dissolves when mixed with water
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Consider a mass initially moving at 7.50 m/s. How does it take to move 3.5 km (Be sure to convert to meters) if it accelerates a
Tomtit [17]
The mass is moving by uniformly accelerated motion, with initial velocity v_i=7.50 m/s and acceleration a=0.55 m/s^2. Its position at time t is given by the following law:
x(t)=v_i t + \frac{1}{2}at^2
where we take the initial position x_i=0 since we are only interested in the distance traveled by the mass.

If we put x(t)=d=3.5 km=3500 m into the equation, the corresponding time t is the time it takes for the mass to travel this distance:
\frac{1}{2}at^2+v_it-d=0
4.9t^2+7.5t-3500 =0
And the two solutions for the equation are:
t=-25.5 s --> negative, we can discard it
t=24.0 s --> this is the solution to our problem
5 0
4 years ago
Determine the molar concentration of 4 moles of HCL dissolved in 2500 ml of solution​
Reptile [31]

Answer:

1.6 molar

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C=number of moles/volume

convert ml to L

V =2.5L

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4 0
1 year ago
Which form of energy is due to an object's motion?
Natali [406]

Answer: kinetic energy

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5 0
3 years ago
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What is the gravitational force between two masses of 15kg each, when their centers are 0.25m? Could you detect this force with
Lunna [17]
Well I don't know !
Let's work it out.

The gravitational force between two objects is

                     F  =  G  ·  M₁·M₂ / R²     .

'G'    is the 'universal gravitational constant'.  We could look it up. 
'M₁'  is the mass of one object
'M₂'  is the mass of the other object 
'R'    is the distance between their centers. 

It looks complicated, but stay with me.  We can do this !
We know all the numbers, so we can calculate the force.

'G'    is  6.67 x 10⁻¹¹ newton·meter² / kg²   (I looked it up.  You're welcome.)
'M₁'  is  15 kg
'M₂'  is  15 kg 
'R'    is  0.25 meter.

Now it's time to pluggum in.

       F  =  G  ·  M₁·M₂ / R²

           = (6.67 x 10⁻¹¹  newton·meter² / kg²) · (15 kg) · (15 kg)  /  (0.25 m²)

           = (6.67 x 10⁻¹¹  ·  15  ·  15 / 0.0625)  N·m²·kg·kg / kg²·m²

           =      2.4 x 10⁻⁷  Newton  .

That a force equivalent to about  0.00000086  of an ounce.
This is the answer to part-a.

Concerning the answer to part-b ...
Personally, I could not detect this force, no matter what kind of equipment
I had. But I am just a poor schlepper engineer, educated in the last Century,
living out my days on Brainly and getting my kicks from YouTube videos. 
I am not pushing the box to the envelope, or thinking outside the cutting
edge ... whatever.
I am sure there are people ... I can't name them, because they keep a
low profile, they stay under the radar, they don't attract a lot of media
attention, their work is not as newsworthy as the Kardashians, and plus,
they seldom call me or write to me ... but I know in my bones that there
are people who have measured the speed of light to NINE significant figures,
aimed a spacecraft accurately enough to take close-up pix of Pluto ten years
later, and detected gravity waves from massive blobs that merged 13 billion
years ago, and I tell you that YES !  THESE guys could detect and measure
a force of  0.86 micro-ounce if they felt like it !
4 0
3 years ago
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