Answer:
the angle of incident is 40°
Explanation:
NQ is the normal to the mirror, therefore
angle NQA =90°
PQA = 50°
incident angle = NQA - PQA
90°- 50° = 40°
note that the angle of reflection is equal to the angle of incident
Protons and Neutrons account for most of an atoms mass
The solution for this problem is:
Let u denote speed.
Equating momentum before and after collision:
= 0.060 * 40 = (1.5 + 0.060) u
= 2.4 = 1.56 u
= 2.4 / 1.56 = 1.56 u / 1.56
= 1.6 m / s is the answer for this question. This is the speed after the collision.
Answer:
979.6 kg/m³
Explanation:
We know pressure P = hρg where h = height of liquid = 10.5 m, ρ = density of liquid and g = acceleration due to gravity = 9.8 m/s²
So, density ρ = P/hg
Since P = 100.8 kPa = 100.8 × 10³ Pa
substituting the values of the variables into the equation for ρ, we have
ρ = P/hg
= 100.8 × 10³ Pa ÷ (10.5 m × 9.8 m/s²)
= 100.8 × 10³ Pa ÷ 102.9 m²/s²
= 0.9796 × 10³ kg/m³
= 979.6 kg/m³
So, the density of the liquid is 979.6 kg/m³
