We have volume of gasoline = 14.0 gallon
Time taken to fill automobile tank = 1.50 minutes
So volume rate = 14.0 gallon/1.50 minutes = 9.33 gallon/ minute
We have density of gasoline = 0.77 kg/L = 6.073 lb/US gal
Mass rate = Density * Volume rate
= 9.33 gallon/ minute*6.073 lb/US gal = 56.68 lb/min
So mass flow rate delivered by the gasoline pump in lbm/min = 56.68
Speed= distance/ time so distance = speed * time= 28 * 20= 560m .. so the answer is 560m.. l hope it helped :)
3.85 pounds is the answer
2.1) (i) W = mg downwards
(ii) N = R = Normal Reaction from the ground upwards
(iii) Fe = Force of engine towards the right
(iv) f = friction towards the left
(v) ma = Constant acceleration towards right.
2.2.1)
v = 25 m/s
u = 0 m/s
∆v = v - u = (25 - 0) m/s = 25 m/s
x = X
∆t = 50 s

a = 0.5 m/s².
2.2.2)
F = ma = 900 kg × 0.5 m/s² = 450 N.
2.2.3)


2.3)
Fe = f + ma
Fe - f = ma
For velocity to be constant,
a should be 0, or, a = 0,
Fe = f = 270 N
2.4.1)
v = 0
u = 25 m/s
a = -0.5 m/s²
v = u + at
t = -u/a = -(25)/(-0.5) = 50 s.
2.4.2)
x = -625/(2×(-0.5)) = 625 m.