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emmasim [6.3K]
3 years ago
14

What do all waves, including sound and light, have in common​

Physics
1 answer:
Schach [20]3 years ago
6 0

Answer:

They all have frequency, wavelength, amplitude, speed and also all transfer energy.

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Define one newton force...<br>No spam..​
djverab [1.8K]

The force applied to make an object of mass 1 kg accelerate by 1 m/s² is equal to one newton.

8 0
3 years ago
Read 2 more answers
A particle is at the position (x,y,z) = (1.0, 2.0, 3.0) m. it is traveling with a vector velocity (-5.3, -4.8, -3.9) m/s. its ma
Alisiya [41]
<1, 2, 3> x (7.6 <-5.3, -4.8, -3.9>) x stands for cross product 

What does the above notation mean? 

Multiply 7.6 to each component of the velocity vector to obtain the linear momentum vector. Find the cross product of the position vector and the linear momentum vector. That gives you the angular momentum vector.

7.6 * -5.3 = -40.28
7.6 * -4.8 = -36.48
7.6 * -3.9 = -29.64

Cross Multiplication
-40.28   1 = -80.56 - (-36.48)
-36.48   2   

-40.28   1 = -120.84 - (-29.64)
-29.64   3    

-36.48   2 = -109.44 - (-59.28)
-29.64   3

answer is (-91.2) - (50.16) + 117.04 = -24.32
5 0
3 years ago
Janet pushes a cart, the cart with a net force of 60N. The mass of the cart was 48 kg. Calculate the carts acceleration
jeka57 [31]

Answer:

a = 1.25m/s^2

Explanation:

Force = mass x acceleration

Given mass M = 48kg and

Force F = 60N

60 = 48 x a

Divide both sides by 48

60/48 = 48 x a/48

1.25 = a

a = 1.25m/s^2

5 0
4 years ago
Violet light of wavelength 427 nm ejects electrons with a maximum kinetic energy of 0.684 eV from a certain metal. What is the w
frutty [35]

Answer:

The work function of the metal is 2.226 eV.

Explanation:

Given;

wavelength of the violet light, λ = 427 nm = 427 x 10⁻⁹ m

maximum kinetic energy, K.E = 0.684 eV

The energy of the incident light is calculated as;

E = hf = \frac{hc}{\lambda} = \frac{6.626 \ \times \ 10^{-34} \ \times\ 3\ \times \ 10^8 }{427 \ \times \ 10^{-9}} = 4.655 \ \times \ 10^{-19} \ J\\\\1 \ eV = 1.6 \ \times \ 10^{-19} \ J\\\\E =( \frac{4.655 \ \times \ 10^{-19} \ J }{1.6 \ \times \ 10^{-19} \ J} ) \ eV\\\\E = 2.91 \ eV

Apply Einstein's photoelectric equation;

E = Ф + K.E

where;

Ф is the work function of the metal

Ф  = E - K.E

Ф  = 2.91 eV - 0.684 eV

Ф  = 2.226 eV.

Therefore, the work function of the metal is 2.226 eV.

5 0
3 years ago
using a weston cadmium cell of 1.0283 v and a standard resistance of .1ohm a potentiometer was adjusted so that 1.0183 m was equ
anyanavicka [17]

Answer:

Explanation:

the value is -8 cm

3 0
3 years ago
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