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olga55 [171]
2 years ago
6

Whats the area of the shape

Mathematics
2 answers:
Brums [2.3K]2 years ago
8 0

Answer:

Step-by-step explanation: what are the dimensions

Len [333]2 years ago
7 0
28kekic01 i can't answer the question with out a picture or numbers.

Step-by-step explanation:
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Which point plotted below has coordinates (4, -2)?
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Point d that is option d
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How old are you now ?<br>​
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Answer: 14

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On a highway, you take 3 seconds to increase your speed from 32 to 35 miles per hour. Your speed increases the same amount each
balandron [24]

Answer:

1 to 30 seconds

Step-by-step explanation:

3 seconds increases your speed from 32 to 35 miles per hour

Hence 3 seconds = 3 miles per hour(35-32 miles)

1 second = 1 mile

The function for the increase per mile is therefore:

f(x)= 1x

Where x is number of seconds travelled on the highway

The domain of a function are the possible input values for x. Since the speed limit on the highway is 65 miles, the input values for x cannot be more than 30 seconds(current speed is 35 miles per hour, 65-35=30)

3 0
3 years ago
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco
kari74 [83]

Answer:

C. \frac{1}{18}

Step-by-step explanation:

Given: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5.

Solution:

Sample space for sum of cards when two cards are drawn at random is \{(1,1),(1,2),(1,3)......(6,6)\}

total number of possible cases =36

Sample space when sum of cards is 8 is \{(3,5),(5,3),(6,2),(2,6),(4,4)\}

Total number of possible cases =5

Sample space when one of the cards is 5 is \{(5,3),(3,5)\}

Total number of possible cases =2

Let A be the event that sum of cards is 8

p(\text{A}) =\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}

p(\text{A})=\frac{5}{36}

Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

p(\frac{\text{B}}{\text{A}})=\frac{2}{5}

Now,

probability that sum of cards 8 is and one of cards is 5

p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})

p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

if sum of cards is 8 then probability that one of the cards is 8 is \frac{1}{18}, option C is correct.

3 0
2 years ago
4/7 × 3/8= show how you got answer
seraphim [82]

Answer:

4/7 × 3/8=0.214285714

Step-by-step explanation:

4/7 × 3/8=0.214285714

8 0
2 years ago
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