Answer:
a) 7a/8; b) 5a/8
Step-by-step explanation:
Given:
AP = 2PQ = 2QB
Calculations:
1. A to the midpoint of QB
a = AP + PQ + QB
If 2PQ = 2QB.
PQ = QB and
AP = 2PQ
∴ a = 2PQ + 2PQ = 4PQ
PQ = a/4
AP = 2PQ = a/2
Let M be the midpoint of QB.
AM = AP + PQ + QM
= a/2 + a/4 + a/8
= 7a/8
2. Midpoints of AP and QB
Let N be the midpoint of AP
NM = NP + PQ + QM
= a/4 +a/4 + a/8 =
= 5a/8
Answer:
So the 1st, 2nd, & 3rd graphs all show continuous data. (I'll attach an image to show which ones I'm talking about)
Explanation:
This is because with continuous data, all points need to connect and it needs to continue. The 4th graph (with just points) would be discrete.
I hope this helps!! :)
Sorry I took so long...
