Segment AB has length "a" and is divided by points P and Q into AP, PQ, and QB, such that AP = 2PQ = 2QB.
1 answer:
Answer:
a) 7a/8; b) 5a/8
Step-by-step explanation:
Given:
AP = 2PQ = 2QB
Calculations:
1. A to the midpoint of QB
a = AP + PQ + QB
If 2PQ = 2QB.
PQ = QB and
AP = 2PQ
∴ a = 2PQ + 2PQ = 4PQ
PQ = a/4
AP = 2PQ = a/2
Let M be the midpoint of QB.
AM = AP + PQ + QM
= a/2 + a/4 + a/8
= 7a/8
2. Midpoints of AP and QB
Let N be the midpoint of AP
NM = NP + PQ + QM
= a/4 +a/4 + a/8 =
= 5a/8
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Answer : The fifth term in the sequence is -2.
Step-by-step explanation :
As we are given that the expression to calculate the term.
The expression is as follows:
where,
n is the number of term
Given:
n = 5
Now putting the value of n in the above expression, we get:
Therefore, the fifth term in the sequence is -2.
Given:
The graphed point is (60,-20).
To find:
The ordered pair that would form a proportional relationship with the given point.
Solution:
If y is proportional to x, then
Where, k is the constant of proportionality.
For the given point,
For option (A),
For option (B),
For option (C),
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The point (-30,10) gives the same value of the constant of proportionality. So, the point (-30,10) forms a proportional relationship with the given point.
Therefore, the correct option is C.