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Elden [556K]
3 years ago
12

Ying Zyiyu covers the first 300 miles of a trip traveling at 60 mph. and the last hundred miles traveling at 40 mph. What was hi

s average speed for the entire trip?
Mathematics
1 answer:
UNO [17]3 years ago
7 0

Answer:

53.33 mph

Step-by-step explanation:

Speed is the rate of change of distance with time. Mathematically,

speed = distance/time

and is measured in miles per hour or meter per second.

To get the average speed over the entire trip, we must get the total time  spent on trip and the total distance, then apply the speed formula

Time for the first 300 miles

= 300/60

= 5 hours

Time spent on the last 100

= 100/40

= 2.5 hours

Total time of the trip = 5 + 2.5

= 7.5 hours

Total distance covered

= 300 miles + 100 miles

= 400 miles

Average speed on the trip

= 400/7.5

= 53.33 miles per hour

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Answer:

12x+4-16x = 0

-4x + 4 = 0

-4x = 0-4

x = -4/-4

x= 1

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3 years ago
What is X-5 in word form
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Answer:

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If you buy a bat and ball for $1.10 and the bat is $1 more than the ball most people would answer that the ball costs 10c. Howev
Marina CMI [18]

Answer: the right cost is $1.05 for a bat and 0.5c for a ball.


Step-by-step explanation:

Let's imagine x in the price of bat and y is the price of the ball

From the infor we know that:

x + y= 1.10 (dollars)

and since the bat is $1 more than the ball we can ensure that:

x - 1 = y

Now we can replace y as follow:

x + x - 1 = 1.10

2x - 1 = 1.10

2x = 1.10 + 1

2x = 2.10

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5 0
3 years ago
There are two major cell phone providers in the Colorado Springs, Colorado area, one called HTC and the other, Mountain Communic
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

Hello!

The objective of this exercise is to compare the "Churn rate" between the two major cell phone providers in colorado springs.

For each provider, the number of subscribers was noted at the beginning and end of a month.

The study variables are:

X₁: Number of customers that cut ties with HTC over a month.

X₂: Number of customers that cut ties with Mountain Communications over a month.

To compare the churn rate of both companies, the parameters of interest are the population proportions of customers that stopped using the companies services over the given period.

The hypotheses of interest are:

H₀: p₁ = p₂

H₁: p₁ ≠ p₂

α: 0.01

The statistic to use is the standard normal approximation:

Z= \frac{('p_1-'p_2)- (p_1-p_2)}{\sqrt{'p(1 - 'p)[\frac{1}{n_1} + \frac{1}{n_2}  ]} } }

Z≈N(0;1)

HTC

n₁= 10000 customers (beginning of the month)

x₁= 190 customers (people that stopped using the company service)

sample proportion 'p₁= x₁/n₁= 190/10000= 0.019

Mountain Communications

n₂= 12285 customers (beginning of the month)

x₂= 215 customers (people that stopped using the company service)

sample proportion 'p₂= x₂/n₂= 215/12285= 0.0175

pooled sample proportion 'p= \frac{x_1 + x_2}{n_1 + n_2} = \frac{190 + 215}{10000 + 12285}

'p= 0.0182

Z_{H_0}= \frac{(0.019 - 0.0175) - 0}{\sqrt{(0.0182*0.9818)[\frac{1}{10000} + \frac{1}{12285}  ]} }

Z_{H_0}= 0.833

The p-value for this test is: 0 .4048

Note: Using the p-value method to decide over a hypothesis test, the decision rule is:

If p-value ≥ α, then you do not reject the null hypothesis.

If p-value < α, then you reject the null hypothesis.

The p-value < α, so the decision is to reject the null hypothesis.

With a significance level of 1%, there is enough evidence to conclude that there is a difference between the churn rate of the two cell phone providers.

I hope it helps!

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Alex_Xolod [135]

Answer:

Options a ans b both are correct.

Step-by-step explanation:

The graph of g(x) = (x + 1) is a transformation of the graph of f(x) = x.

If we examine the transformed function, then we will get, the value of g(x) is added by 1 unit for a corresponding value of x as in the original function.

So, the translation is 1 unit up.

Again, the value of x in the transformed graph is 1 unit less than the x-value of the original equation for a corresponding value of g(x).

So, the translation is 1 unit left.  

Therefore, options a and b both are correct. (Answer)

5 0
3 years ago
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