So the best way to do these is concentration1 (%) × volume1 = concentration2 × volume2
Or C1V1 + C2V2 = C3V3, where C1 = 100% (bc ALL pecans), V1 = 6 lbs, C2 = 70%, C3 = 82%:
100%×6 + 70%×v2 = 82%×(6+v2)
100%=1.00, 70%=.7, 82%=.82
note: if none is poured out then v3 = v1+v2
6 + .7v2 = .82 (6+v2)
6 + .7v2 = 4.92 + .82v2
6 + .7v2 -.7v2 = 4.92 + .82v2 -.7v2
6 = 4.92 + .12v2
6-4.92 = 4.92-4.92 + .12v2
1.08 = .12v2
.12v2/.12 = 1.08/.12
v2 = 9 lbs
that's only v2!!!
For the final poundage, we need v3:
v3 = 6 + v2 = 6 + 9 = 15 lbs
Answer: frequency
Step-by-step explanation:
If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942_______________
Solve the equation:

Reduce the fractions at the left side so that they have the same denominator:

Numerators must be equal:

I hope this helps. =)
Tags: <em>rational equation fraction solution algebra</em>
If M <span>is the midpoint of AB then AB = 2AM
8x - 6 = 2(3x + 3)
8x - 6 = 6x + 6
8x - 6x = 6 + 6
2x = 12
x = 12/2
x = 6
AM = 3x + 3 = 3*6 + 3 = 18 + 3 = 21 units
</span>
Answer:
a) P value = 0.0013
b) No, it is not plausible that the silicon content of the water is no greater than it was 10 years ago
Step-by-step explanation:
The null hypothesis here is “Mean is equal to 5” while alternate hypothesis is that “Mean is greater than 5”
Given
Mean = 5, x’ = 5.4 and sigma = 1.2 and n = 85
Z = x-u’/sigma/sqrt n
Substituting the given values, we get –
Z = 3.02
A) P value = 0.0013 which is less than 0.05 and thus we will reject the null hypothesis
B) There is enough evidence to reject the null hypothesis