Since we know a circle has 360 degrees, the sector bounded by a 90 degree arc will be a quarter of circle (360/90 = 4). Then, to calculate the area of that sector, we can calculate the total area of the circle of radius 10, and then divide it by 4.

The area of a cirlce of radius r is:

$A=\pi r^2$

Then, the area of the sector would be:

$A_s=\frac{\pi r^2}{4}$ $A_s=\frac{\pi(10m)^2}{4}=\frac{100\pi}{4}m^2$ $A_s=25\pi m^2$

4 0

1 year ago

Really need help to number 10 ASAP!!

AnnyKZ [126]

The original volume is 1,260.
If you double each dimension, the equation goes from 14*9*10 to 28*18*20
The answer to the second equation is 10,080.
The second answer is 8 times as much as the original.

8 0

4 years ago

Sec^2x-2secx.cosx+cos^2x=tan^2x-sin^2x<br><br> Prove the identity

alexdok [17]

Hello.

sin²x + cos²x = 1

cos²x = 1 - sin²x

secx = 1/cosx

sec²x = tan²x + 1

5 0

2 years ago

Solve the quadratic equation x2 + 2mx + m = 0

zaharov [31]

Answer:

-m(+/-)sqrt(m^2-m)=x.

Step-by-step explanation:

7 0

3 years ago