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3 years ago

15

When you have an equal sign you use an open dot. True? or false?

2 answers:

sleet_krkn [62]3 years ago

5 0

Answer:

False

Step-by-step explanation:

Open dot is used when the boundary is not included

Example:

2 < x < 5

Open dots at 2 and 5

kipiarov [429]3 years ago

4 0

Answer:

False

Step-by-step explanation:

It is false because a opened circle is for greater than or less than, and a closed dot is less than or equal to

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A ball is dropped from a certain height. The function below represents the height f(n), in feet, to which the ball bounces at th

natali 33 [55]

Answer:

9 represents the initial height from which the ball was dropped

Step-by-step explanation:

Bouncing of a ball can be expressed by a Geometric Progression. The function for the given scenario is:

$f(n)=9(0.7)^{n}$

The general formula for the geometric progression modelling this scenario is:

$f(n)=f_{0}(r)^{n}$

Here,

$f_{0}$ represents the initial height i.e. the height from which the object was dropped.

r represents the percentage the object covers with respect to the previous bounce.

Comparing the given scenario with general equation, we can write:

$f_{0}$ = 9

r = 0.7 = 70%

i.e. the ball was dropped from the height of 9 feet initially and it bounces back to 70% of its previous height every time.

7 0

3 years ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

4 years ago

The density of lead is 11.4g/cm^3 at 25 degrees C. Calculate the volume occupied by 25.0g of lead

ElenaW [278]

Answer:

2.193 cm³

Step-by-step explanation:

density is mass divided by volume:

$density = \frac{mass}{volume}$

you can manipulate the formula by multiplying with volume:

$density \times volume = mass$

then dividing by density:

$volume = \frac{mass}{density}$

in this case:

$volume = \frac{25g}{11.4 \frac{g}{cm} } = 2.193 { \: cm}^{3}$

6 0

1 year ago

Please tell me the answer for <br> Factorise 15p square - 7q square

oksian1 [2.3K]

Answer:

I do not think you can simplify it any further

Step-by-step explanation:

If you mean 15p squared - 7 q squared

Because they have different variables; p and q cannot be combined unless it is multiplication or division.

3 0

4 years ago

+22 + +14 + -10 + +10 + -22 + +14 = n

professor190 [17]

Answer:

Solve for n:

28 = n

Hint: | Reverse the equality in 28 = n in order to isolate n to the left hand side.

28 = n is equivalent to n = 28:

Answer: n = 28

Step-by-step explanation:

6 0

3 years ago