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larisa [96]
4 years ago
12

1 . According to the nebular theory, the solar system formed from ?

Physics
2 answers:
oee [108]4 years ago
8 0
1. The correct answer is B. The nebular theory states that the solar system is the result of the collapse, for unknown reasons, of a large, thin cloud of dust and gas. After this collapse<span>, the pockets of gas and dust started gathering into denser regions. As these regions collected more and more matter, they started to rotate, which led to the accumulation of a big ball in the </span>center<span>, the Sun, and </span>flattenedmatter around, the protoplanetary disc. Then the planets got formed by the accretion of this disc, which eventually created the planets. 

2. The correct answer is D. The terrestrial<span> planets were formed by </span>accretion<span> of material that was denser in its constitution. This is the reason why they remained closer to the sun - they were heavier than gas, that is the material the Jovian planets are mostly made of.</span><span />
mars1129 [50]4 years ago
4 0

Answer:

1. d

2. d

3.a

Explanation:i just took the quiz

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You have an empty 20 oz. soda bottle and you blow air over the opening to excite a fundamental standing wave. Now, you slice off
Tatiana [17]

Answer:

The frequency of the standing wave in the second case is higher than that in the first case

Explanation:

The frequency and wavelength of a wave are related.

The moment you sliced the bottle, you've reduced the wavelength of the bottle.

When wavelength decreases, frequency increases and vice versa.

So, When frequency increases in the second case, more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.

3 0
4 years ago
If the clock runs slow and loses 15 s per day, how should you adjust the length of the pendulum?
Shkiper50 [21]

Answer:

L= 1 m,   ΔL = 0.0074 m

Explanation:

A clock is a simple pendulum with angular velocity

         w = √ g / L

Angular velocity is related to frequency and period.

         w = 2π f = 2π / T

We replace

        2π / T = √ g / L

        T = 2π √L / g

We will use the value of g = 9.8 m / s², the initial length of the pendulum, in general it is 1 m (L = 1m)

With this length the average time period is

           T = 2π √1 / 9.8

           T = 2.0 s

They indicate that the error accumulated in a day is 15 s, let's use a rule of proportions to find the error is a swing

           t = 1 day (24h / 1day) (3600s / 1h) = 86400 s

         e= Δt = 15 (2/86400) = 3.5 104 s

The time the clock measures is

           T ’= To - e

           T’= 2.0 -0.00035

           T’= 1.99965 s

Let's look for the length of the pendulum to challenge time (t ’)

           L’= T’² g / 4π²

           L’= 1.99965 2 9.8 / 4π²

           L ’= 0.9926 m

Therefore the amount that should adjust the length is

           ΔL = L - L’

           ΔL = 1.00 - 0.9926

           ΔL = 0.0074 m

8 0
4 years ago
how does distance change when the amount of effort force is increasesd while the amount of work done remains the same?
nlexa [21]
Could you supply u with some answer choices please?
8 0
4 years ago
Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equ
Irina-Kira [14]

Answer:

Magnitude of the net force on q₁-

Fn₁=1403 N

Magnitude of the net force on q₂+

Fn₂= 810 N

Magnitude of the net force on q₃+

Fn₃= 810 N

Explanation:

Look at the attached graphic:

The charges of the same sign exert forces of repulsion and the charges of   opposite sign exert forces of attraction.

Each of the charges experiences 2 forces and these forces are equal and we calculate them with Coulomb's law:

F= (k*q*q)/(d)²

F= (9*10⁹*3*10⁻⁶*3*10⁻⁶)(0.01)² =810N

Magnitude of the net force on q₁-

Fn₁x= 0

Fn₁y= 2*F*sin60 = 2*810*sin60° = 1403 N

Fn₁=1403 N

Magnitude of the net force on q₃+

Fn₃x= 810- 810 cos 60° = 405 N

Fn₃y= 810*sin 60° = 701.5 N

Fn_{3} = \sqrt{405^{2}+701.5^{2}  }

Fn₃ = 810 N

Magnitude of the net force on q₂+

Fn₂ = Fn₃ = 810 N

6 0
3 years ago
A block moves up a 30 degree incline under the action of three applied forces. F1 is horizontal and of magnitude 40 N. F2 is nor
Alja [10]

Answer

given,

F₁ is horizontal = 40 N

F₂ is normal = 20 N

F₃ is parallel = 30 N

work done by

W₂ = 0 as force is acting perpendicular to the direction of motion.

as the motion moved to 0.8 cm

W₃ = F₃ x d

W₃ = 30 x 0.8

W₃ = 24 J

W₁ = F₁ x d

W₁ = F₁ cos ∅ x d

W₁ = 40 cos 30⁰ x 0.8

W₁ = 27.21 J

4 0
4 years ago
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