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Lostsunrise [7]
3 years ago
12

Drop a rock from a 5-m height and it accelerates at 9.81 m/s^2 and strikes the ground 1s later. Drop the sane rock from a height

of 2.5m and it’s acceleration of fall is about
A. The same amount
B.greater than the second height
C. Less than the second height
D. Acceleration
Physics
1 answer:
KiRa [710]3 years ago
8 0

Answer:

A. The same amount

Explanation:

The acceleration at which objects free falls to the ground on Earth is constant and its value is always 9.81 m/s^2, regardless of their mass (in this problem we neglect air resistance).

So, it doesn't matter if the two rocks are different or they are launched from different heights: their acceleration will be exactly the same.

This can be proved this way: first of all, the force of gravity exerted on every object is equal to the weight of the object,

F=mg

where m is the mass of the object and g the acceleration of gravity.

However, we also know for Newton's second law that

F=ma

where a is the acceleration of the object.

Combining the two equations,

ma=mg\\a=g

So, the acceleration of an object in free fall is exactly the acceleration of gravity.

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Difference between the fertility rate and mortality rate of developed and least development countries
dybincka [34]

Answer:

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5 0
3 years ago
suppose 384g of steam originally at 100C is quickly cooled to produce liquid water at 31C. How much heat must be removed from th
dlinn [17]

Answer:

Q=977216.256\ J=977.216\ kJ

Explanation:

Given:

  • mass of  steam, m=384\ g
  • temperature of steam, T_{is}=100^{\circ}C
  • temperature of resultant water, T_{fw}=31^{\circ}C

We have,

  • latent heat of vapourization of water, L=2256\ J.g^{-1}
  • specific heat capacity of water, c=4.186\ J.g^{-1}

<em>When we cool the steam of 100°C then firstly it loses its latent heat to convert into water of 100°C and the further cools the water.</em>

<u>Now the heat removed from steam to achieve the final state of water:</u>

\rm Q=latent\ heat\ of\ vapourization+sensible\ heat\ of\ water

Q=m(L+c.\Delta T)

Q=384(2256+4.186\times (100-31))

Q=977216.256\ J=977.216\ kJ

3 0
3 years ago
When the cylinder is displaced slightly along its vertical axis it will oscillate about its equilibrium position with a frequenc
Nesterboy [21]

Answer:

w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

Explanation:

We can simulate this system as a physical pendulum, which is a pendulum with a distributed mass, in this case the angular velocity is

          w² = mg d / I

In this case, the distance d to the pivot point of half the length (L) of the cylinder, which we consider long and narrow

         d = L / 2

The moment of inertia of a cylinder with respect to an axis at the end we can use the parallel axes theorem, it is approximately equal to that of a long bar plus the moment of inertia of the center of mass of the cylinder, this is tabulated

        I = ¼ m r2 + ⅓ m L2

        I = m (¼ r2 + ⅓ L2)

now let's use the concept of density to calculate the mass of the system

        ρ = m / V

        m = ρ V

the volume of a cylinder is

         V = π r² L

          m =  ρ π r² L

let's substitute

        w² = m g (L / 2) / m (¼ r² + ⅓ L²)

        w² = g L / (½ r² + 2/3 L²)

        L >> r

         w = √[g /L (½ r²/L2 + 2/3 ) ]

When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

4 0
3 years ago
Consider eight,eight-cubic centimeter (8 cm3) sugar cubes stacked so that they form a single 2 x 2 x 2 cube. How does the surfac
In-s [12.5K]
To find the surface area of a single cube we first nees to take the cube root of 8cm3 which is 2.

Now we know that the length of each side is 2 and we can find the area of one side by doing 2x2 which is 4.

To find the total surface area of one cube we do 4 times 6 side giving us a total of 24cm2.

To find the total surface area of the 8 individual cubes, we multiply 24cm2 by 8 to give us a total of 192cm2.

Now to find the total surface area of the one large cube, we know that each side of one of the small cubes is 4cm2 and the large cube is set up so that there are two levels of four cubes right on top of each other. So, the total area of each side of the large cube is 4cm2 times 4 which gives us 16cm2.

Then we multiply 16cm2 by 6 sides to give us a total surface area of 96cm2.

The ratio of the surface area of the single large cube comapred to the total surface area of the single cubes is 96:192

We can further simplify this ratio:

96:192

48:96

24:48

12:24

6:12

3:6

1:2
5 0
3 years ago
___ acceleration occurs when an object speeds up
AleksandrR [38]

Explanation:

Acceleration is defined as the change in velocity over time.

When there is an increment or increase in the magnitude of velocity of a moving body then it is known as positive acceleration.

Whereas when there is a decrease in magnitude of velocity of a moving body then it is known as negative acceleration.

Thus, we can conclude that positive acceleration occurs when an object speeds up.

3 0
3 years ago
Read 2 more answers
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