Drop a rock from a 5-m height and it accelerates at 9.81 m/s^2 and strikes the ground 1s later. Drop the sane rock from a height
1 answer:
Answer:
A. The same amount
Explanation:
The acceleration at which objects free falls to the ground on Earth is constant and its value is always , regardless of their mass (in this problem we neglect air resistance).
So, it doesn't matter if the two rocks are different or they are launched from different heights: their acceleration will be exactly the same.
This can be proved this way: first of all, the force of gravity exerted on every object is equal to the weight of the object,
where m is the mass of the object and g the acceleration of gravity.
However, we also know for Newton's second law that
where a is the acceleration of the object.
Combining the two equations,
So, the acceleration of an object in free fall is exactly the acceleration of gravity.
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The time required by the particles are as follows:
a. t = 1.5 seconds
b. t = 3 seconds
c. t = 0.4 seconds
<h3>What is the time required?</h3>The time required for the particles to be at several distances apart is calculated using the equation of motion given below:
a) Time required to be 30 m apart:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51 - 30
S1 + S2 = 21
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 21
2t^2 + 11t - 21 = 0
Solving for time, t by factorization, t = 1.5 seconds
b) Time required to meet:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 51
2t^2 + 11t - 51 = 0
Solving for time, t by factorization, t = 3 seconds
c) Time required for velocity of P is ¾ of the velocity of Q:
Using the equation of motion: V = u + at
Vp = 3/4 Vq
4Vp= 3Vq
Substituting the values:
4(5 + t) = 3(6 + 3t)
5t = 2
t = 0.4 seconds
Learn more about distance, velocity and acceleration at: brainly.com/question/14344386
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here in the given situation if monkey starts free fall at the same instant when veterinarian shoots towards it then we know that vertical component of motion of monkey and the dart will be same as under gravity
so here the dart will always hit the monkey because they both moves under same acceleration
so here for the angle we can use
now we have
H = 3 m
L = 87.5 m
now we will have
so angle will be 1.96 degree above the ground