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Wittaler [7]
2 years ago
8

Light rays from an object after passing through a convex lens form an image at the focal point behind the lens (opposite side of

the object). What is the actual position of the object? at the focal point in front of the lens at twice the focal length between the focal point and twice the focal length at a great distance, effectively infinite between the focal point and the lens NextReset
Physics
2 answers:
Colt1911 [192]2 years ago
8 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.


The actual position of the object is between the focal point and twice the focal length and <span>at the focal point in front of the lens. I think it would be A and C. </span>
BaLLatris [955]2 years ago
3 0

Answer:

effectively infinite between the focal point and the lens

Explanation:

Light rays from an object after passing through a convex lens form an image at the focal point behind the lens (opposite side of the object).

Now from lens formula we know that

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

now we know that image forms at focal point

so we will have

d_i = f

now from the equation above

\frac{1}{f} + \frac{1}{d_o} = \frac{1}{f}

so we will have

\frac{1}{d_o} = 0

so position of object is at infinite distance from lens

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Answer:

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A plane has a mass of 360,000 kg takes-off at a speed of 300 km/hr. i) What should be the minimum acceleration to take off if th
melomori [17]

Answer:

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Given the data in the question;

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F = 625 kN

Therefore, required force that the engine must exert to attain acceleration is 625 kN

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