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SSSSS [86.1K]
2 years ago
12

2. You race a child that is exactly half your mass up identical ladders. If you took 5 s, and the child took 7 s, who did more w

ork? Who had greater power?
Physics
1 answer:
topjm [15]2 years ago
5 0

Answer:

You did more work, and you also had greater power.

Explanation:

Work is defined as a force doing a motion.

Particularly, when we lift an object of mass M by a distance H, the work is written as:

W = M*g*H

where g is the gravitational acceleration, then M*g = weight.

In this case, you and the child both are at the same distance to the ground after both of you finish the race, but your mass is twice the mass of the child.

Then if the child's mass is M, then the child's work is:

Wc = M*g*H

your work will be:

W = (2*M)*g*H

meaning that your work is twice the work.

Power is defined as the amount of work you do in a given amount of time.

So, if you needed 5 seconds to do the work W = (2*M)*g*H, then the (average) power will be equal to the quotient between the total amount of work you did and the time it took to do it.

Then your work is:

P = W/5s = (2*M)*g*H/5s

And the power for the child will be:

Pc = Wc/7s = M*g*H/7s

Your power has a larger numerator and a smaller denominator then is easy to see that you had greater power.

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A ball is kicked at a speed of 16m/s at 33° and it eventually returns to ground level further down field.
saw5 [17]

Hi there!

We can begin by calculating the time taken to reach its highest point (when the vertical velocity = 0).

Remember to break the velocity into its vertical and horizontal components.

Thus:

0 = vi - at

0 = 16sin(33°) - 9.8(t)

9.8t = 16sin(33°)

t = .889 sec

Find the max height by plugging this time into the equation:

Δd = vit + 1/2at²

Δd = (16sin(33°))(.889) + 1/2(-9.8)(.889)²

Solve:

Δd = 7.747 - 3.873 = 3.8744 m

4 0
3 years ago
Read 2 more answers
Two charges, one of 2.50μC and the other of -3.50μC, are placed on the x-axis, one at the origin and the other at x = 0.600 m
aev [14]

Answer:

Explanation:

Given

charge of first body q_1=2.5\ mu C

charge of second body q_2=-3.5\ mu C

Particle 1 is at origin and particle 2 is at x=0.6\ m

third Particle which charge +q must be placed left of 2.5\mu C because it will repel the q charge while -3.5\mu C will attract it

suppose it is placed at a distance of x m

F_{1q}=\frac{kq(2.5)}{x^2}

F_{2q}=\frac{kq(-3.5)}{(0.6+x)^2}

F_{1q}+F_{2q}=0

\frac{kq(2.5)}{x^2}+\frac{kq(-3.5)}{(0.6+x)^2}=0

\frac{kq(2.5)}{x^2}=\frac{kq(3.5)}{(0.6+x)^2}

\frac{0.6+x}{x}=(\frac{3.5}{2.5})^{0.5}

0.6+x=1.1832x

x=3.27\ m

5 0
3 years ago
How much wood could a wood chuck chuck if a wood chuck could chuck wood
krek1111 [17]

Answer:

As much wood as a woodchuck could chuck, If a woodchuck could chuck wood.

Explanation:

3 0
2 years ago
What os the term for the smallest bit into which chemical substance can be divided and still have the properties of that substan
Ostrovityanka [42]

That's a molecule of the substance.  You can break the molecule down further, into the atoms that make it up, but those don't have the properties of the original  'compound'.

Here's an example:

-- Sodium is a soft, slippery metal, that explodes when water touches it.

-- Chlorine is a poisonous green gas.

When an atom of Sodium and an atom of Chlorine combine, they make one molecule of a substance called "Sodium Chloride".  That's SALT !  It isn't green, it isn't a gas, it isn't poisonous, it isn't soft and slippery, and it doesn't explode when water touches it.

3 0
3 years ago
an empty boat floats in water with 10% of its volume submerged. and when it is loaded with 1200kg , the volume submerged will in
Lostsunrise [7]

Let volume of empty boat be = 100% = 1V

and mass of boat be M

In water 10%, 0.1V of the volume is submerged.

Mass, m of 1200kg increases the submerging from 10%, 0.1V to 70%, 0.7V

M leads to 0.1V boat submerging

boat submerging.

M + 1200kg leads to 0.7V boat submerging.

This is 60%, 0.6 V increase

By comparison

(M+1200kg) * 0.1V = 0.7V * M

0.1M + 120kg = 0.7M

120kg = 0.7M - 0.1M

120kg = 0.6M

M = (120/0.6)kg

M = 200kg.

The mass of the boat is 200kg.

4 0
2 years ago
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