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Advocard [28]
4 years ago
13

What is the voltage in a circuit if the current is 6.2 A and the resistance is 18 ohms?

Physics
1 answer:
Nitella [24]4 years ago
4 0
We already know the formula:
Voltage = Current * Resistance
In the given question, there are numerous information's that are already given.
Current = 6.2 A
Resistance = 18 ohms
Then
Voltage = 6.2 * 18 Volts
             = 111.6 Volt
So, the voltage in the circuit will be 111.6 volts. I hope it helps you.
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Calculate the power of the elevator if it can raise 290 kg of mass 30 flights of stairs (300 m) in 17 seconds
Advocard [28]

Answer:

Power =  50204 [watts]

Explanation:

We know that the power is defined by the following expression:

Power = Work/time

where:

Power [watts]

time [seconds]

The work done will be the following:

Work = Force * distance [Joules]

Force[Newtons]

distance[meters]

Force = mass* gravity

Force=290 [kg]*9.81[m/s^2] =2844.9[N]

Work = 2844.9[N]*300[m] = 853470[J]

Therefore

Power = 853470 / 17 = 50204 [watts]

5 0
3 years ago
A bird on a long migration flies 63 kilometers per hour for 2900
Fed [463]

Answer:

46

Explanation:

2900 divided by 63 (2900/63)

-  46.03174603

Rounded to the nearest whole number

is 46.

THE ANSWER IS 46

5 0
3 years ago
If you place a balloon in the freezer it will______
matrenka [14]

B. Deflate because volume is inversely proportional to temperature

8 0
3 years ago
Suppose the charged sphere is made from a conductor, rather than an insulator. Do you expect the magnitude of the force between
meriva

Answer:

* Point charge outside the radius of the sphere r> R, the force in the two systems is the same

* Point charge inside the sphere  r <R,  therefore the force in the system with the insulating sphere is greater

Explanation:

To answer this question let's use the relation

          F = q E

with q being the point charge and E the electric field created by the sphere.

If we use Gauss's law

The electric field flux is proportional to the wax charge within the surface.

Let's analyze our situation.

* Point charge outside the radius of the sphere

          r> R

where R is the radius of the sphere and r the distance from the center of the sphere to the point charge

in this case the waxed charge for the insulating and conducting sphere is the same, therefore the force in the two systems is the same

* Point charge inside the sphere

           r <R

conductive sphere.

     As the charges are mobile, they are located on the surface of the sphere and there is no waxed charge within a Gaussian surface that passes through the point charge, therefore the electric field is zero and consequently the force

             F = 0

insulating sphere

      Charges cannot move therefore there is a fraction of charge within a surface that passes through the point charge, consequently the electric field is different from zero

            Fe> 0

for this second position the force on the conducting sphere is zero

therefore the force in the system with the insulating sphere is greater

4 0
3 years ago
A thin slab of Germanium is used as a Hall Effect probe. How would you orient a magnetic field to make the side facing out of th
Cerrena [4.2K]

Answer:

the magnetic field must go in a direction parallel to the page perpendicular to the current.

Explanation:

The Hall effect is the voltage produced by the movement of electrons due to the effect of electric and magnetic fields in a material

            F = eE + v x B

The electric field goes in the direction of the current that is opposite to the direction of the electrons, therefore the magnetic force must be perpendicular to it.

Therefore, if the current goes in a direction parallel to the page, in the x direction, the magnetic field must be perpendicular to it if we use the rule of the right wizard,

thumb points in the direction of E, x axis parallel page

The fingers extended should go parallel to the page in the direction and up

The palm is the direction of the Force, where the voltage will be produced points out the page, this is for positive charges, as in germanium the charges are negative, the real force goes into the page.

Therefore the electrons accumulate on the inside of the page and the voltage is negative in this part.

Therefore the voltage is positive on the outside of the sheet. In conclusion the magnetic field must go in a direction parallel to the page perpendicular to the current.

6 0
3 years ago
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