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3 years ago

Is SiO2 Polar or Non-polar?

Chemistry

2 answers:

Annette [7]3 years ago

7 0

The answer is SiO2 is Nonpolar.

nirvana33 [79]3 years ago

6 0

<span>SiO2 is a </span>non-polar compound.

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In the reaction 2 H2 + O2m 2 H20, how

Tresset [83]

Answer:

Option F. 3moles

Explanation:

The equation for the reaction is given below:

2H2 + O2 —> 2H2O

from the equation,

2moles of H2 required 1mole of O2.

Therefore, 6moles of H2 will require = 6/2 = 3moles of O2

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3 years ago

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What is the bohr model for pottasium

guapka [62]

Potassium is an alkali metal with the chemical symbol K. It has an atomic number of 19, meaning that it has 19 positively charged protons. It also contains 19 electrons, which have a negative charge, and 20 neutrons, which do not hold a charge
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3 years ago

Explain which material is likely to slow the flow of electrical charges the most? *

babunello [35]

Answer:

The material which is likely to slow the flow of electric charges the most is PVC plastic ‾ \text{\underline{PVC plastic}} PVC plastic.

Explanation:

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1 year ago

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I NEED HELP PLEASE, THANKS! :)

marin [14]

Answer:

$\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}$

Explanation:

1. Calculate the moles of copper(II) hydroxide

$\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}$

2. Calculate the molecules of copper(II) hydroxide

$\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}$

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2 years ago

Write a reflection about your learning in this unit. Your reflection should be at least 3 sentences. Use the following sentence

Vera_Pavlovna [14]

Answer:

This unit has encouraged a deeper understanding of the world and it's guiding principles. While it was initially challenging for me to determine if a change was physical or chemical, this unit provided me with the information necessary to determine the type. With this knowledge, I can now interrelate with other properties and believe that this new ability will assist in future units as well. Thank you!

Explanation:

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1 year ago