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BaLLatris [955]
3 years ago
11

How many moles are there in 67.2 grams of h2

Chemistry
1 answer:
yarga [219]3 years ago
7 0

Answer: 33.3 moles

Explanation: 67.2 g H2 = 67.2/2.016 = 33.3 moles

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To make a 1.0L dilute of 0.5M from a stock solution of 12M, how much solution will be needed?
Cerrena [4.2K]

Answer:

V_{concentrated}=0.042L=4.2mL

Explanation:

Hello,

In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:

M_{diluted}V_{diluted}=M_{concentrated}V_{concentrated}

Clearly, the concentrated solution is 12M and the diluted solution is 0.5 M, thus, the volume of the concentrated solution we should take is:

V_{concentrated}=\frac{M_{diluted}V_{diluted}}{M_{concentrated}} =\frac{0.5M*1.0L}{12M}\\ \\V_{concentrated}=0.042L=4.2mL

Best regards.

6 0
3 years ago
The molecular mass of bromophenol blue is 692.0. Find the atomic mass for copper from a periodic table.
Tanya [424]
<span>The atomic mass for copper is 63.546 amu. Copper is typically reddish orange in color and has a melting point of 1981.4 degrees Fahrenheit. It is classified as a transition metal and has an atomic number of 29.</span>
4 0
3 years ago
Epsom salts are hydrates of magnesium sulfate. the formula for epsom salt is mgso4·7h2o. if a 7.834 g sample is heated until con
vesna_86 [32]
1. For the first question, we must find the mass of the anhydrous salt, MgSO₄. The molar mass for MgSO₄·7H₂O is 246.47 g/mol, while that of MgSO₄ is 120.37 g/mol.

7.834 g MgSO₄·7H₂O * 1 mol MgSO₄·7H₂O/246.47 g * 1 mol MgSO₄/1 mol MgSO₄·7H₂O * 20.37 g MgSO₄/mol = <em>0.647 g MgSO₄</em>

2. Mass of Water = Mass of sample - Mass of anhydrous sale
Mass of water = 7.834 - 0.647 = 7.19 g
Percent Water in Hydrate = 7.19/7.834 * 100 = <em>91.74%</em>
5 0
3 years ago
Calculate the molarity of a solution that has 2.02 mol KNO3 in a 250.0<br> mL solution.
SCORPION-xisa [38]

Explanation:

Molarity = M = mol/1 liter

in sol 250 mL there are KNO3 2.02 mol

in sol 1000 mL there are KNO3 = 2.02/250 × 1000

= 8.08 mol/liter

5 0
3 years ago
A careless student forgets to label one of their reagent containers. They know it contains one of the following solutions: 0.1 M
antiseptic1488 [7]

Answer:

0.1 M NaCl

Explanation:

This question reminds of of the solubility rules. Let us recall that all chlorides are soluble except those of lead, mercury II and silver which are insoluble in water.

The following reaction will occur leading to the formation of a precipitate;

Pb(NO3)2(aq) + 2NaCl(aq) -------> 2NaNO3(aq) + PbCl2(s)

The white precipitate formed is  PbCl2.

4 0
3 years ago
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