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3 years ago

Which alignment of the Sun, Moon, and Earth causes a lunar eclipse?

Chemistry

2 answers:

hram777 [196]3 years ago

8 0

Answer:

A lunar eclipse occurs when the Moon passes directly behind the Earth into its umbra (shadow). This can occur only when the Sun, Earth, and Moon are aligned exactly with the Earth in the middle. Hence, a lunar eclipse can only occur the full moon phase

Explanation:

please mark me brainlist

irina [24]3 years ago

5 0

Answer:

A sun

Explanation:

because sun has heat and gives light

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Write einstein's equation that explains the energy from nuclear reactions. _________ use the caret symbol (^) to show an exponen

Katen [24]

I would say it should be Einstein's famous equation of e=mc^2 which means energy =mass x the speed of light squared. With this equation Einstein showed that energy comes from a mass travelling at the speed of light squared which is a fundamental equation to explain physical phenomena.

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4 years ago

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Which temperature in Celsius (°C) does this thermometer show? –8° 0° 25° 32°

natka813 [3]

Answer:

0° Celsius

Explanation:

The thermometer shows 0° Celsius which corresponds to 32° F.

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4 years ago

Explain the water cycle in your own words. make sure u tell the steps in order

gregori [183]

Answer:

Collection - Evaporation - Condensation - Precipitation

Explanation:

The Water cycle is a series of continuous events that cause rain

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2 years ago

The following reaction is part of the electron transport chain. Complete the reaction and identify which species is reduced. The

Olegator [25]

Answer:

$FADH_2 + Q --> FAD + QH_2$

The reactant that is reduced is $FADH_2$

Explanation:

The complete equation is as below:

$FADH_2 + Q --> FAD + QH_2$

Recall that oxidation involves the gain of electrons while reduction involves the loss of electrons.

In the above reaction, $FADH_2$ loses electrons to coenzyme Q and becomes reduced to FAD, hence the oxidizing agent. Coenzyme Q gains electrons and becomes oxidized to $QH_2$ , hence the reducing agent.

In order words, $FADH_2$ is reduced while coenzyme Q is oxidized.

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4 years ago

Calculate the pH for each of the following cases in the titration of 25.0 mL of 0.150 M sodium hydroxide with 0.150 M HBr(aq). (

Taya2010 [7]

Answer:

a) pH = 13.176

b) pH = 13

c) pH = 12.574

d) pH = 7.0

e) pH = 1.46

f) pH = 1.21

Explanation:

HBr + NaOH ↔ NaBr + H2O

∴ equivalent point:

⇒ mol acid = mol base

⇒ (Va)*(0.150mol/L) = (0.025L)*(0.150mol/L)

⇒ Va = 0.025 L

a) before addition acid:

NaOH → Na+ + OH-

⇒ C NaOH = 0.150 M

⇒ [ OH- ] = 0.150 M

⇒ pOH = - Log ( 0.150 )

⇒ pOH = 0.824

⇒ pH = 14 - pOH

⇒ pH = 13.176

b) after addition 5mL HBr:

⇒ C NaOH = (( 0.025)*(0.150) - (0.005)*(0.150)) / (0.025 + 0.005) = 0.1 M

⇒ C HBr = (0.005)*(0.150) / ( 0.03 ) = 0.025 M

⇒ [ OH- ] = 0.1 M

⇒ pOH = 1

⇒ pH = 13

c) after addition 15mL HBr:

⇒ C NaOH = ((0.025)*(0.150) - (0.015)*(0.150 ))/(0.04) = 0.0375 M

⇒ C HBr = ((0.015)*(0.150))/(0.04) = 0.0563 M

⇒ [ OH- ] = 0.0375 M

⇒ pOH = 1.426

⇒ pH = 12.574

d) after addition 25mL HBr:

equivalent point:

⇒ [ OH- ] = [ H3O+ ]

⇒ Kw = 1 E-14 = [ H3O+ ] * [ OH- ] = [ H3O+ ]²

⇒ [ H3O+ ] = 1 E-7

⇒ pH = 7.0

d) after addition 40mL HBr:

⇒ C HBr = ((0.04)*(0.150) - (0.025)*(0.150)) / (0.04 + 0.025) = 0.035 M

⇒ [ H3O+ ] = 0.035 M

⇒ pH = 1.46

d) after addition 60mL HBr:

⇒ C HBr = ((0.06)*(0.150) - (0.025)*(0.150)) / (0.06+0.025) = 0.062 M

⇒ [ H3O+ ] = 0.062 M

⇒ pH = 1.21

8 0

4 years ago

Read 2 more answers