<u>Answer:</u> The mass of
produced will be 17.8 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
....(1)
<u>For Sodium hydroxide:</u>
Given mass of sodium hydroxide = 10 g
Molar mass of ![NaOH=[(1\times 22.989)+(1\times 15.999)+(1\times 1.008)]g/mol=39.996g/mol](https://tex.z-dn.net/?f=NaOH%3D%5B%281%5Ctimes%2022.989%29%2B%281%5Ctimes%2015.999%29%2B%281%5Ctimes%201.008%29%5Dg%2Fmol%3D39.996g%2Fmol)
Putting values in above equation, we get:

For the given chemical equation:

By Stoichiometry of the reaction:
2 moles of sodium hydroxide produces 1 mole of sodium sulfate.
So, 0.25 moles of sodium hydroxide will produce =
of sodium sulfate.
Now, to calculate the mass of sodium sulfate, we use equation 1:
Moles of sodium sulfate = 0.125 moles
Molar mass of ![Na_2SO_4=[(2\times 22.989)+(1\times 32.065)+(4\times 15.999)]g/mol=142.039g/mol](https://tex.z-dn.net/?f=Na_2SO_4%3D%5B%282%5Ctimes%2022.989%29%2B%281%5Ctimes%2032.065%29%2B%284%5Ctimes%2015.999%29%5Dg%2Fmol%3D142.039g%2Fmol)
Putting values in equation 1, we get:

Hence, the mass of
produced will be 17.8 grams.