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Effectus [21]
4 years ago
13

For each telecommunications bonding conductor there shall be a label and it shall be located on the conductor as close as practi

cable to the point of termination.
Physics
1 answer:
shepuryov [24]4 years ago
3 0

Answer:

There shall be a LABEL

Explanation:

The label is to enable the maintenance personal or the user to identify the individual conductor from each other during removal and installation or when maintenance task is being carried out on the system. This is to avoid the users of the system form plugging the conductor incorrectly.

For example, if there are four conductors label A, B, C, and D there will be four connection point label same way. By this, the user will not plug conductor A to plug B.

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John often sees squiggly lines when he looks at a bright sky or white paper. His doctor says that they are called eye floaters,
trapecia [35]

Answer- It's B, i double checked it on a few websites

8 0
3 years ago
Read 2 more answers
A bicycle of mass m requires 50 J of work to move from rest to a final speed v. If the same amount of work is performed during t
insens350 [35]

Answer:

The final speed of the second bicycle is (v·√2)/2

Explanation:

The mass of the given bicycle = m

The amount of work required to move the bicycle from rest to speed v = 50 J

The final speed of the first bicycle = v

The mass of the second bicycle = 2m

Therefore, from conservation of energy, we have;

Work required by the first bicycle = Kinetic energy gained by the bicycle

The kinetic energy = 1/2·m·v²

∴ Energy required by the first bicycle = 50 J = 1/2·m·v²

Given that the same amount of work is performed on the second bicycle, we have;

Work performed on the second bicycle = 50 J = kinetic energy of second bicycle = 1/2·(2·m)·v₂²

Also, given that 50 J = 1/2·m·v², we have;

Work performed on the second bicycle = 50 J = 1/2·m·v²= 1/2·(2·m)·v₂²

1/2·m·v²= 1/2·(2·m)·v₂²

m·v² = 2·m·v₂²

v² = 2·v₂²

v₂ = √(v²/2) = v/√2 = (v·√2)/2

v₂ = (v·√2)/2

The final speed of the second bicycle = v₂ = (v·√2)/2.

3 0
3 years ago
If you decrease the distance between successive crests of a wave, this changesA. The frequency.B. The wavelength.C. The speed.D.
Feliz [49]

Answer:

option E

Explanation:

The correct answer is option E

Writing the relation between wavelength and frequency

      f = \dfrac{v}{\lambda}

f is the frequency

v is the velocity of wave

λ is the wavelength

From the above expression we can clearly see that frequency is inversely proportional to wavelength.

When the distance between the two successive crest is decreased then wave length of the wave also decrease.

If wavelength of the wave decreases then frequency of the wave increase.

hence, we can say that both wavelength and the frequency changes.

8 0
3 years ago
A car travels a distance of 200 miles in 3.5 hours in a given trip. What is the average speed of the car in that
erica [24]

Taking into account the definition of speed, the average speed of the car in the trip is 57.14 \frac{miles}{hour}.

<h3>Definition of speed</h3>

Speed is a physical magnitude that relates the displacement of an object and the time it takes to make this change in position.

So, the speed can be defined as the amount of space traveled per unit of time with which a body moves and can be calculated using the expression:

speed=\frac{displacement}{time}

Speed has units of \frac{distance}{time}, such as \frac{meters}{second} or \frac{miles}{hour}.

<h3>Average speed of the car</h3>

In this case, you know that:

  • displacement= 200 miles
  • time= 3.5 hours

Replacing in the definition of speed:

speed=\frac{200 miles}{3.5 hours}

<u><em>speed= 57.14 </em></u>\frac{miles}{hour}

Finally, the average speed of the car in the trip is 57.14 \frac{miles}{hour}.

Learn more about velocity:

brainly.com/question/4418301

brainly.com/question/24990123

brainly.com/question/14244558

brainly.com/question/25288184

#SPJ1

7 0
2 years ago
A car has a mass of 2,500 kg. The car is accelerating at 0.5 m/s2. What is the net force acting on the car?
tekilochka [14]

Answer:

force:mass*acceleration

2500kg*0.5m/s2

1250N

6 0
3 years ago
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