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2 years ago

Find the pH and the pOH of the solution

1 answer:

5 0

Ok so the PH for each solution will be
1.) 1.638 2.) 5.2 3.) 12.524
This is found using the formula: pH = - log [H3O+].
And the pOh for each one will be
1.) 12.362 2.) 8.8 3.) 1.4763
This is found by the formula pOH = -log10[OH-]
Hope this is useful

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What is the density of an 84.7 g sample of an unknown substance if the sample occupies 49.6cm cubed

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Answer:

1.70 g.cm⁻³

Solution:

Data Given;

Mass = 84.7 g

Volume = 49.6 cm³

Density = ?

Formula Used;

Density = Mass ÷ Volume

Putting values,

Density = 84.7 g ÷ 49.6 cm³

Density = 1.70 g.cm⁻³

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irga5000 [103]

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Calculate the vapor pressure at 35ºC of a solution made by dissolving 20.2 g of sucrose (C12H22O11)in 60.5 g of water. The vapor

sukhopar [10]

Answer:

P' = 41.4 mmHg → Vapor pressure of solution

Explanation:

ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution (P')

Xm = Mole fraction for solute (Moles of solvent /Total moles)

Firstly we determine the mole fraction of solute.

Moles of solute → Mass . 1 mol / molar mass

20.2 g . 1 mol / 342 g = 0.0590 mol

Moles of solvent → Mass . 1mol / molar mass

60.5 g . 1 mol/ 18 g = 3.36 mol

Total moles = 3.36 mol + 0.0590 mol = 3.419 moles

Xm = 0.0590 mol / 3.419 moles → 0.0172

Let's replace the data in the formula

42.2 mmHg - P' = 42.2 mmHg . 0.0172

P' = - (42.2 mmHg . 0.0172 - 42.2 mmHg)

P' = 41.4 mmHg

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2 years ago