All categories

3 years ago

Chemistry screen shot below plzzzzzzz help i've been stuck forever

Chemistry

2 answers:

Oxana [17]3 years ago

8 0

Answer:

True

Explanation: Imagine the Electrons is by the nucleus which give more energy.

slamgirl [31]3 years ago

4 0

The answer would be true :)

You might be interested in

Choose the aqueous solution below with the lowest freezing point. These are all solutions of nonvolatile solutes and you should

Ymorist [56]

Answer:

B. 0.075 m (NH4)3PO4

Explanation:

Our strategy here is to recall the van´t Hoff factor, i, for the colligative properties of electrolyte solutions which appears as the consequence that electrolytes disociate completely in their solutions in water.

Thus in this problem we need to determine i and then realize the one with the lowest freezing point will have the biggest i ( all the concentrations are equal) since

ΔTf = i m Kf

Substance van´t Hoff factor

Li I 2

(NH4)3PO4 4

NaIO4 2

KCN 2

KNO2 2

The correct answer is B. 0.075 m (NH4)3PO4

4 0

4 years ago

Energy in the amount of 420 J is added to a 35 g sample of water at a temperature of 10°C. What is the final temperature of the

Vsevolod [243]

The final temperature of the water, T2 = 38.57°C

Temperature can be defined as a measure of the degree of hotness or coldness of a physical object (body). Thus, it is measured with a thermometer and its units are degree Celsius (°C), Fahrenheit (°F) and Kelvin (°K).

A calorie refers to the amount of heat required to raise the temperature of a gram of water by one (1) degree Celsius (1°C).

Given the following data:

Quantity of energy = 420J

Mass = 35 grams

Initial temperature, T1 = 10°C

The specific heat capacity of water is 4.2 J/g°C.

To find the final temperature of the water (T2):

Mathematically, the quantity of energy (heat capacity) is given by the formula;

$Q = mcdt$

Where;

Q represents the heat capacity or quantity of heat.

M represents the mass of an object.

C represents the specific heat capacity of water.

dt represents the change in temperature.

Substituting the values into the formula, we have;

$420 = 3.5 \; * \; 4.2 \; * \; dt$

$420 = 14.7 \; * \; dt\\\\dt = \frac{420}{14.7}$

Change in temperature, dt = 28.57°C

Next, we would solve for the final temperature by using this formula;

$dt = T2 - T1$

$28.57 = T_{2} - 10\\\\T_{2} = 28.57 \; + \; 10\\\\T_{2} = 38.57$

Final temperature, T2 = 38.57°C

Therefore, the final temperature of the water, T2 is equal to 38.57°C

For more information visit: brainly.com/question/22736508

7 0

3 years ago

The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles

hoa [83]

Note: You are calculating mass which is determine the gram(g)
You will have to cancel out the mol
(28.97 g/mol) * mol will give grams by itself
Given the mass 3.33 moles of air
28.97 g/mol * 3.33 mol = 96.47 grams
Solution: 96.5 grams

5 0

3 years ago

What happens to the decaying neutron during beta decay?

slega [8]

A neutron will be converted into a proton, and the process creates an electron and Anrineutrino (while in beta+) Decay, a proton will never converted to a neutron and processess will create a position and the electroneutrio (B+) is also known as Emission

6 0

3 years ago

Calculate q (in units of joules) when 1.850 g of water is heated from 22 °C to 33 °C. Report only the numerical portion of your

Minchanka [31]

When q is the heat energy in joules (J)

so, according to this formula, we can get q (in joule unit):

q = M*C*ΔT

when M is the mass of the water sample = 1.85 g

C is the specific heat capacity of water = 4.18 J/g.°C

and Δ T is the difference in temperature (Tf-Ti) = 33 - 22 = 11°C

So, by substitution, we will get the value of q ( in Joule):

∴ q = 1.85 g * 4.18 J/g.°C * 11 °C

= 85 J

5 0

3 years ago