Answer:
Following are the answer to this question:
Explanation:
The answer are:
1) ketopentose
2) Triose
3) Aldose
4) Ketose
5) Glucose
6) Aldohexose
- The pentose has 2-position contain a personal ketone group.
- The triose is a monosaccharide or simple sugar that contains three atoms of carbon.
- The Aldose and ketose are simple carbohydrates, both also called monosaccharides. In aldose, it has a functional group of aldehydes within its structure. The ketose sugars have workable ketone groups. Stereoisomerism has been found in aldose sugars that contain more than three carbon atoms.
- Glucose is also one of the main molecules which function as plant and animal energy sources. It's also derived from plant sap and seems to be present in the bloodstream of humans, that's why it is called "blood sugar."
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The aldohexose is a hexose is a group of aldehydes on one end, it has a total of 16 possible aldohexose stereoisomers in four chiral centers.
From the equation;
P1V1=P2V2
V2=P1V1÷P2
V2=29.0×13.0÷3.50
V2=107.71L
therefore V2=107.7L
Answer:
Explanation: It has been given that the temperature of the water decreases when chromium chloride is dissolved in water. Thus fall in the temperature explains the fact that the bond energies of the reactants have more energy rather than the products.
a) Thus the heat of the solution is endothermic in nature as more energy is needed to break the reactant molecules.
b) The combined ionic bond strength of CrCl2 and inter molecular forces between water molecules must be stronger than the attractive forces between the water molecules and chromium and chloride ions as the reaction is endothermic in nature thus more energy would be required to break the bonds between the reactants hence making them more stronger.
Answer:
In voltaic cells, oxidation occurs at an anode (-), reduction at a cathode (+), and electrons flow from anode to cathode. In electrolytic cells, oxidation occurs at an anode, reduction occurs at a cathode, and electrons flow from anode to cathode.
Explanation:
Answer:
Freezing point: <u>32 ºF (0ºC)</u>
Melting point: <u>32 ºF (0ºC)</u>
Boiling point: <u>203°F (95°C)</u>
Explanation:
At the boiling point, <u>the vapor pressure of a liquid equals the external pressure</u>. The normal melting point and boiling point of water at 1 atm are 0°C and
100°C, respectively. Decreasing the pressure under 1 atm (what happens when we are at high altitudes) will lower the boiling point since the external pressure will be lower, and it will become equal with the vapor pressure at a lower temperature.
However, the melting point and freezing point will stay unaffected since they don't depend on air-pressure; so at 0 or 5000 meters they will still be 0°C (remember that, <u>since water is a pure substance, the freezing and melting points will be the same</u>).