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jarptica [38.1K]
3 years ago
9

Give the nuclear symbol for the isotope of phosphorus for which a=31? enter the nuclear symbol for the isotope (e.g., 42he).

Chemistry
1 answer:
Bogdan [553]3 years ago
8 0
A = number of mass = 31 => number of protons + number of neutrons = 31

Phosphours, Z = atomic number = 15 = number of protons

Symbol of the element phosphorus = P

=> The symbol of the isotope is the symbol of the element, P, with the number of mass, 31, to the left, as a superscript, and the atomic number, 15, to the left, as a suscript.
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How many moles of br2(l) (mm = 159.80 g/mol) are in 13.9 ml of liquid bromine? the density of br2(l) is 3.12 g/ml?
diamong [38]

Answer:

             Moles  =  0.271 mol

Solution:

Step 1: Calculate Mass of Br₂ as;

                               Density  =  Mass  ÷  Volume

Solving for Mass,

                               Mass  =  Density  ×  Volume

Putting values,

                               Mass  =  3.12 g.mL⁻¹  ×  13.9 mL

                               Mass  =  43.36 g

Step 2: Calculate Moles of Br₂ as;

                               Moles  =  Mass  ÷  M.Mass

Putting values,

                               Moles  =  43.36 g ÷  159.80 g.mol⁻¹

                              Moles  =  0.271 mol

7 0
3 years ago
How many hydrogen bonds will be found within an alpha helix that is 18 amino acids long?.
LekaFEV [45]

An alpha helix which is 18 amino acids long will have 12 hydrogen bonds.

<h3>What is alpha helix (α-helix) ?</h3>

The alpha helix (α-helix) is a common in the secondary structure of proteins and is a right hand-helix conformation in which every backbone N−H group hydrogen bonds to the backbone C=O. group of the amino acid located four residues earlier along the protein sequence.

The alpha helix is stabilized by hydrogen bonds (shown as dashed lines) from the carbonyl oxygen of one amino acid to the amino group of a second amino acid.

Because the amino acids connected by each hydrogen bond are four apart in the primary sequence, these main chain hydrogen bonds are called "n to n+4.

Learn more about protein structure here ;

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5 0
2 years ago
According to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in which order?
saveliy_v [14]

According to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in alphabetical without taking prefixes into name.

A hydrocarbon would be an organic molecule in organic chemistry that is made completely of hydrogen as well as carbon. A good example of group 14 hydrides includes hydrocarbons. In general, hydrocarbons lack color and are hydrophobic. Typically, their faint smells are compared to that of gasoline and lighter fluid.

  • The longest unbroken carbon chain should be found and named.
  • Name the groups that make up this chain but instead identify them.
  • Beginning at the end of the chain closest to a substituent group, fraction the chain sequentially.
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Therefore, according to the iupac convention, alkyl substituents on a hydrocarbon chain should be listed in alphabetical without taking prefixes into name.

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8 0
1 year ago
How many grams of glucose, C6H12O6, in 2.47 mole?
statuscvo [17]
First, we need to find the atomic mass of C_{6}H_{12}O_{6}.

According to the periodic table:
The atomic mass of Carbon = C = 12.01
The atomic mass of Hydrogen = H = 1.008
The atomic mass of Oxygen = O = 16

As there are 6 Carbons, 12 Hydrogens and 6 Oxygens, therefore:
The molar mass of  C_{6}H_{12}O_{6} = 6 * 12.01 + 12 * 1.008 + 6 * 16

The molar mass of  C_{6}H_{12}O_{6} = 180.156 grams/mole

Now that we have the molar mass of  C_{6}H_{12}O_{6}, we can find the grams of glucose by using:

mass(of glucose in grams) = moles(of glucose given in moles) * molar mass(in grams/mole)

Therefore,
mass(of glucose in grams) = 2.47 * 180.156
mass(of glucose in grams = 444.99 grams

Ans: Mass of glucose in grams in 2.47 moles = 444.99 grams

-i
6 0
3 years ago
Read 2 more answers
What ion carries two negative charges and is isoelectronic with k+?
lutik1710 [3]
The answer is:   "  S²⁻  " .
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