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Oksi-84 [34.3K]
4 years ago
11

Is salt a Elements or a Compound?

Chemistry
2 answers:
n200080 [17]4 years ago
8 0

Answer:

Salt is a compound because it is made of only NaCl, not because it has only Sodium and Chlorine, in which case it will be mixture of the two elements

CO2 (Carbon Dioxide) is a Compound

gold metal is the element

Sodium is called an element and water is called a compound

Oxygen is an element. A compound is two or more elements chemically combined.

Tju [1.3M]4 years ago
4 0

Answer:

1. Salt is a compound

2. CO2 is a compound

3. Gold is an element

4. Na is an element

5. Oxygen is an element

6. C6H2O6 is a compound

Explanation:

if it is on the periodic table it is an element

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A Bronsted-Lowry acid is defined as a substance that ________. A Bronsted-Lowry acid is defined as a substance that ________. in
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Answer: A Bronsted-Lowry acid is defined as a substance that acts as a proton donor.

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A substance that is able to donate a proton or hydrogen ion to another substance is a Bronsted-Lowry acid.

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HCl \rightleftharpoons H^{+} + Cl^{-}

Thus, we can conclude that a Bronsted-Lowry acid is defined as a substance that acts as a proton donor.

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3 years ago
Micheal has a substints that he puts in container 1 the substance has a volume of 5 cubic meters
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Answer: Solids and liquids don't suddenly change their volumes.

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The heat capacity of air is much smaller than that of water, and relatively modest amounts of heat are needed to change its temp
LekaFEV [45]

Answer:

Q=9.2x10^5J

t=614s=10.2min

Explanation:

Hello,

In this case, we can compute the energy by using the following formula for air:

Q=nCp\Delta T

Whereas the moles of air are computed via the ideal gas equation at room temperature inside the 5.5m x 6.5m x 3.0m-room:

n=\frac{PV}{RT}\\\\V=5.5m*6.5m*3.0m=107.25m^3*\frac{1000L}{1m^3}=107250L\\ \\n=\frac{1atm*107250L}{0.082\frac{atm*L}{mol*K}*298.15K}\\ \\n=4386.8mol

Now, we are able to compute heat, by considering that the temperature raise is given in degree Celsius or Kelvins as well:

Q=4386.8mol*21\frac{K}{mol*K}*10K \\\\Q=9.2x10^5J

Finally, we compute the time required for the heating by considering the heating rate and the required heat, shown below:

t=\frac{9.2x10^5J}{1.5\frac{kJ}{s}*\frac{1000J}{1kJ} } \\\\t=614s=10.2min

Regards.

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