Answer:
Explanation:
Given the amount of heat absorbed and the amount of substance in moles, we may calculate the heat of vaporization. Heat of vaporization is defined as the amount of heat per 1 mole of substance required to evaporate that specific substance.
Based on the value of heat of vaporization, we will identify the substance. Firstly, let's calculate the heat of vaporization:
Secondly, let's use any table for heat of vaporization values for substances. We identify that the heat of vaporization of is 18.7 kJ/mol
<span>*it will change the geometry
changes postion of the lone pairs and atoms so that they are furthest apart</span><span />
Characteristics of a Precipitate:
A precipitate is characterized by the following properties:
Appears as a solid species.
Settled down at the bottom of the reaction pot.
Insoluble in the corresponding solvent.
Answer:
1429.32 mmHg
Explanation:
Initial Pressure P1 = 3000.0mmHg
Initial Temperature T1 = 500.0°C + 273 = 573 K ( Converting to kelvin temperature)
Final Temperature T2 = 0.00°C + 273 = 273 K ( Converting to kelvin temperature)
Final Pressure P2 = ?
The pressure of a given amount of gas is directly proportional to the absolute temperature provided volume remains constant.
This is given by the mathematical expression;
P1 / T1 = P2 / T2
Inserting the values;
3000 / 573 = P2 / 273
P2 = 273 * 3000 / 573
P2 = 1429.32 mmHg